I believe they will sell a total of 23,250 tickets
Here is the equation you should use: x + 2x - 12 = 180
You will be solving for x.
Combine like terms then add twelve to both sides of the equation.
3x = 192
Divide by 3 on both sides of the equation.
x = 64
Now, plug 64 in the equation for x.
2(64) - 12 = 116
x² + y² = 5
y = 2x/3 + 1
In a simple way to find the intersections you can just throw the y value in the other equation, so
x² + y² = 5
x² + (2x/3 + 1)² = 5
x² + (2x/3)² + 2.2x/3.1 + 1² = 5
x² + 4x²/9 + 4x/3 + 1 = 5
13x²/9 + 4x/3 + 1 - 5 = 0
13x²/9 + 4x/3 - 4 = 0
Multiply by 9
13x² + 12x - 36 = 0
Δ = b² - 4.a.c
Δ = 12² - 4 . 13 . -36
Δ = 144 - 4. 13 . -36
Δ = 2016
There are 2 real roots.
x = (-b +- √Δ)/2a
x' = (-12 + √2016)/2.13
x'' = (-12 - √2016)/2.13
x' = 32,8998886412873 / 26
x'' = -56,8998886412873 / 26
x' = 1,2653803323572037
x'' = -2,188457255434127
Rounding
x' = 1,27
x'' = -2,19
Now we need to put this value in the y equation to know the y coordinate.
y = 2x/3 + 1
y' = 2.1,27/3 + 1
y' = 2,54/3 + 1
y' = 1,8466666...
y' = 1,85
y = 2x/3 + 1
y'' = 2.(-2,19)/3 + 1
y'' = -4,38/3 + 1
y'' = -0,46
So the points are: (1,27;1,85) and (-2,19;-0,46)
38 x 1 = 1
38 x 0.1 = 3.8
38 x 0.01 = 0.38
Answer:
grams of gold=8x10^12 g
Step-by-step explanation:
first we calculate the volume of the ocean this is achieved by multiplying the area by the depth
A=3.63x10^8 km^2=3.63x10^14 m^2
V=AxL
V=3.63x10^14 x 3800=1.3797x10^18m^3=1.3797x10^21L
then we multiply the volume in liters by the concentration of gold in the ocean per liter
grams of gold=1.3797x10^21 x 5.8x10^-9=8x10^12 g