(-2,-5)
The first goal with equations like these is to get one of the variables to go away. You can do that by adding/subtracting one equation from the other. Then you solve for the one variable. Then you plug that answer into one of the original equations and solve.
Step-by-step explanation:
slope formula when it's perpendicular : m1 × m = -1
Now Differentiate the quadratic function given.
d/dx ( x^2 - x + 1 ) at an x value of -1 from the point "(-1 , 3 )"
= 2x - 1 .... plug in the x value
= 2 × -1 - 1 = -3.
Use this equation...
y - y1 = m(x - x1)
m = slope = derivative at x = -1
y1 = value found by subbing -1 into the original function
x1 = the x value often given.
y - 3 = 1/3 (x + 1)
= 1/3x + 1/3 + 3
y = 1/3x + 10/3.
not sure about this one - it probably intersects at the x & y intercepts of the equation of the normal line.
y = 0 + 10/3 = 10/3
1/3x = 0 - 10/3
x = -10/3 / 1/3 = -10
so the point .... (-10 , 10/3)
Answer:
I am sorry I missed your slave and the not year old friend and the not year old friend and the not year old old man was born to the point where she spent a good thing for a woman and she had been working on a good thing for her and I am wondering if you could give her expenses for her family to go with the not
Answer:
q(x)= 2x+5
r(x)=6
b(x)=x+4
Step-by-step explanation:
I have found what is missing in your question: Rewrite 2x^2+13x+26/x+4 in the form q(x)+r(x)/b(x).
First, we have to divide the polynomial by x+4 and remember that is x times 2x.
By multiplying this we are going to get 
and now we are doing separation of it and getting 
and getting 
Because 5 is showing x times 5 we are going to multiply (x + 4) with 5 and that is 5x + 20.
Now when we can get more simplified we are having:
Answer:
38 degrees
Step-by-step explanation:
just know
