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3 years ago

Rewrite in the form . Then find q(x) and r(x).

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

3 0

Answer:

q(x)= 2x+5

r(x)=6

b(x)=x+4

Step-by-step explanation:

I have found what is missing in your question: Rewrite 2x^2+13x+26/x+4 in the form q(x)+r(x)/b(x).

First, we have to divide the polynomial by x+4 and remember that is x times 2x.

By multiplying this we are going to get $2x^{2} + 8x$ and now we are doing separation of it and getting $2x^{2} + 13x + 26$ and getting $2x^{2} + 13x + 26/ x + 4 = 2x^{2} +8x/x+4=5x+26/x+4=2x + 5x+26/x+4$

Because 5 is showing x times 5 we are going to multiply (x + 4) with 5 and that is 5x + 20.

$5x+26/x+4 = 5x + 20/x+4 = 6/ x+4=5 + 6/x+4$

Now when we can get more simplified we are having:

$2x^{2} +13+26/x+4=2x + 5= 6/x+4$

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Solve the system of equations:x + 3y - z = -4 2x - y + 2z = 13 3x - 2y - z = -9

tatiyna

Answer:

The solution to the system of equations is

$\begin{gathered} x=\frac{179}{13} \\ \\ y=-\frac{279}{39} \\ \\ z=-\frac{48}{13} \end{gathered}$

Explanation:

Giving the system of equations:

$\begin{gathered} x+3y-z=-4\ldots\ldots\ldots\ldots\ldots\ldots..........\ldots\ldots\ldots\ldots.\ldots\text{.}\mathrm{}(1) \\ 2x-y+2z=13\ldots\ldots...\ldots\ldots\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots.(2) \\ 3x-2y-z=-9\ldots\ldots\ldots.\ldots\ldots\ldots\ldots....\ldots\ldots.\ldots\ldots\ldots\text{.}\mathrm{}(3) \end{gathered}$

To solve this, we need to first of all eliminate one variable from any two of the equations.

Subtracting (2) from twice of (1), we have:

$5y-4z=-21\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots..\ldots..\ldots\ldots.\ldots..\ldots\text{...}\mathrm{}(4)$

Subtracting (3) from 3 times (1), we have

$3y-5z=-3\ldots\ldots...\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots\ldots\ldots\ldots\ldots..\ldots\ldots(5)$

From (4) and (5), we can solve for y and z.

Subtract 5 times (5) from 3 times (4)

$\begin{gathered} 13z=-48 \\ \\ z=-\frac{48}{13} \end{gathered}$

Using the value of z obtained in (5), we have

$\begin{gathered} 3y-5(-\frac{48}{13})=-3 \\ \\ 3y+\frac{240}{13}=-3 \\ \\ 3y=-3-\frac{240}{13} \\ \\ 3y=-\frac{279}{13} \\ \\ y=-\frac{279}{39} \end{gathered}$

Using the values obtained for y and z in (1), we have

$\begin{gathered} x+3(-\frac{279}{39})-(-\frac{48}{13})=-4 \\ \\ x-\frac{279}{13}+\frac{48}{13}=-4 \\ \\ x-\frac{231}{13}=-4 \\ \\ x=-4+\frac{231}{13} \\ \\ x=\frac{179}{13} \end{gathered}$

8 0

1 year ago

Make w the subject of <br> Y-aw=2w-1

Luda [366]

So you're gonna take add 1 to both sides and add aw to both sides also
y+1=2w+aw
then you factorize the w
y+1=w(2+a)
divide 2+a in both sides
y+1/2+a=w
the answer is
y+1/2+a=w

4 0

3 years ago

Read 2 more answers

Nine tenths of the grade 9 class are in the gym. If these students are divided into three equal groups, what fraction of the cla

Dahasolnce [82]

Times by 3. Then divide the top backup by 3 to get 9/30. 9/30+9/30+9/30=27/30=9/10.

3 0

3 years ago

A function rule takes an input, and converts it into an output, y, by decreasing twice the input by 4. what is the output for th

Harman [31]

Answer:

when the input = 4

Then the output = 6

Step-by-step explanation:

It is stated that a function rule takes an input, and converts it into an output, y, by decreasing twice the input by 4.

Let 'x' be the number

Decreasing twice the number 'x' by 4 = 2x-4

Now,

Given the input x = 5

As the output will decrease twice the input (x=5) by 4

Thus, the output = 2(5)-4 = 10-4 = 6

Therefore,

when the input = 4

Then the output = 6

3 0

2 years ago

Can someone plz help me? <3

OverLord2011 [107]

Answer:

C - 52

Step-by-step explanation:

z = 12 x = 2

(You do indices first!)

2 x 2 x 2 = 8

8 x 5 = 40

12 + 40 = 52

I hope this helps, have a good day! :D

5 0

2 years ago