Question

Rewrite in the form . Then find q(x) and r(x).

Answer 1

Answer:

q(x)= 2x+5

r(x)=6

b(x)=x+4

Step-by-step explanation:

I have found what is missing in your question: Rewrite 2x^2+13x+26/x+4 in the form q(x)+r(x)/b(x).

First, we have to divide the polynomial  by x+4 and remember that is x times 2x.

By multiplying this we are going to get $2x^{2} + 8x$ and now we are doing separation of it and getting $2x^{2} + 13x + 26$ and getting $2x^{2} + 13x + 26/ x + 4 = 2x^{2} +8x/x+4=5x+26/x+4=2x + 5x+26/x+4$

Because 5 is showing x times 5 we are going to multiply (x + 4) with 5 and that is 5x + 20.

$5x+26/x+4 = 5x + 20/x+4 = 6/ x+4=5 + 6/x+4$

Now when we can get more simplified we are having:

$2x^{2} +13+26/x+4=2x + 5= 6/x+4$