Answer:
173.83 mmHg is the vapor pressure of a ethylene glycol solution.
Explanation:
Vapor pressure of water at 65 °C=
Vapor pressure of the solution at 65 °C=
The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.
Mass of ethylene glycol = 22.37 g
Mass of water in a solution = 82.21 g
Moles of water=
Moles of ethylene glycol=
173.83 mmHg is the vapor pressure of a ethylene glycol solution.
Answer:
19.9 atoms
Explanation:
Grams --- Moles --- Atoms
You're converting from atoms (molecules) to moles.
You do not have to calculate the mass of "di phosphorus pentoxide."
Since you're already given 1.2x10^25 atoms, you start with that. You need to cancel out the atoms, so you need Avogadro's number as shown in the image.
(This has nothing to do with the problem) But in case if you're wondering, the "di" in phosphorus means there's 2 phosphorus and the "pent" means that there are 5 oxygens. So P2O5. Go to your periodic table, multiply their respective atomic masses. You would multiply phosphorus twice and oxygen 5 times. And add them up to get the overall mass.
I hope this helped!
