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3 years ago

A _________________ is the path of energy transfer from producer to consumers.

Chemistry

1 answer:

Verizon [17]3 years ago

3 0

Answer: Food chain

Explanation: none

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When you calculate the Ksp of calcium fluoride, CaF2, and the concentration of the F- ion is 4.2 x 10-4M, what is the concentrat

polet [3.4K]

Calculate its molar solubility in a saturated aqueous solution that is also 0.050 M in fluoride ion, F-. Ksp = (x)(2x + 0.05)2. 2x = 4.210 4

7 0

2 years ago

According to the kinetic molecular theory, which statement describes the particles in a sample of an ideal gas?

MakcuM [25]

Answer:

The motion of the gas particles is random and in a straight-line. A sample of gas is contained in a closed rigid cylinder.

I hope this helps you if not soo advance sorry :)

3 0

3 years ago

Which pair of atoms has the highest electronegativity difference?

rjkz [21]

The B. Ca-F pair has the greatest electronegativity difference.

Electronegativities <em>increase from the lower left to the upper right</em> in the Periodic Table.

Ca is closest to the lower left, and F is in the upper right, so the Ca-F bond has the greatest electronegativity difference.

4 0

4 years ago

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The ph of 0.010 m aqueous aniline is 8.32. What is the percentage protonated?

LekaFEV [45]

Answer : The percentage aniline protonated is, 0.0209 %

Explanation :

First we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-8.32\\\\pOH=5.68$

Now we have to calculate the hydroxide ion concentration.

$pOH=-\log [OH^-]$

$5.68=-\log [OH^-]$

$[OH^-]=2.09\times 10^{-6}M$

The equilibrium chemical reaction will be:

$NH_3+H_2O\rightleftharpoons NH_4^++OH^-$

From the reaction we conclude that,

Concentration of $OH^-$ ion = Concentration of $NH_4^+$ ion = $2.09\times 10^{-6}M$

Now we have to calculate the percentage aniline protonated.

$\text{percentage aniline protonated}=\frac{2.09\times 10^{-6}M}{0.010M}\times 100$

$\text{percentage aniline protonated}=0.0209\%$

Thus, the percentage aniline protonated is, 0.0209 %

7 0

3 years ago

Copper metal (Cu) reacts with silver nitrate (AgNO3) in aqueous solution to form Ag and Cu(NO3)2. An excess of AgNO3 is present.

aev [14]

we are given the reaction Cu + 2AgNO3 ---> Cu(NO3)2 + 2Ag. This means for every mole Cu used, there are 2 moles of Ag produced. In this case, given 31.75 g Cu, converting to moles through molar mass and using stoichiometric ratio and the molar mass of Ag, the mass Ag produced is 107.9 grams.

8 0

3 years ago

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