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1 year ago

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help meeeeeeeeeeeeeeeeeee pleaseee!!!!help meeeeeeeeeeeeeeeeeee pleaseee!!!!help meeeeeeeeeeeeeeeeeee pleaseee!!!!help meeeeeeee

eeeeeeeeeee pleaseee!!!!help meeeeeeeeeeeeeeeeeee pleaseee!!!!help meeeeeeeeeeeeeeeeeee pleaseee!!!!

1 answer:

sineoko [7]1 year ago

6 0

Answer:

15095.39

Step-by-step explanation:

$13000(1+(0.03)/4)^{(4)(5)} \approx 15095.39$

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One book costs $2.98 how much does four books cost

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4 years ago

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whats the difference between the square root of 25 the square root of negative 25 and the square root of plus minus 25?

Dmitrij [34]

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3 years ago

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A crawling tractor sprinkler is located as pictured below, 100 feet South of a sidewalk. Once the water is turned on, the sprink

deff fn [24]

Answer:

a) see below

b) 32 minutes after turn-on

c) 52 minutes after turn-on

d) 20 minutes

e) 6856.6 ft²

Step-by-step explanation:

a) We have elected to put the origin at the point where the hose crosses the south edge of the sidewalk. Units are feet. Then the sprinkler starts at (0, -100). After 1 hour, 3600 seconds, the sprinkler is 1800 inches, or 150 ft north of where it started, so stops at (0, 50).

The lines forming the sidewalk boundaries are y=0 and y=10.

__

b) Water will first strike the sidewalk when the sprinkler is 20 feet south of it, or 80 feet north of where it started. The sprinkler travels that distance in ...

(80 ft)(12 in/ft)/(1/2 in/s)(1 min/(60 s)) = 32 min . . . time to start sprinkling sidewalk

__

c) The sprinkler has to travel to a point 130 ft north of its starting position for the water to fall north of the sidewalk. That distance is traveled in ...

(130 ft)(2/5 min/ft) = 52 min . . . time until end of sprinkling sidewalk

Note that we have combined the scale factors in the expression of part b into one scale factor of (2/5 min/ft).

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d) The difference of times in parts b and c is the time water falls on the sidewalk: 20 minutes.

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e) In one hour, the sprinkler travels a distance of ...

(60 min)(5/2 ft/min) = 150 ft

Of that distance, 10 feet is sidewalk. So, the sprinkler covers an area of grass that is a 140 ft by 40 ft rectangle and a circle of 20 ft radius. The total area of that is ...

A = LW + πr² = (140 ft)(40 ft) +π(20 ft)² = (14+π)(400) ft² ≈ 6856.6 ft²

The area of grass watered in 1 hour is about 6856.6 ft².

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4 years ago

If you prove that △ABD is congruent to △CDB, which general statement best describes what you have proved?

fredd [130]

Answer:

A: Opposite sides of a parallelogram are congruent

Step-by-step explanation:

The only diagonal involved is BD, so none of the statements regrading diagonals has been proven. The only thing proven is ...

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AD ≅ CB . . . . opposite sides are congruent

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2 years ago

Which of the following statements are true about the given rational equation? check all of the boxes that apply. 4 x 6 1 x2 = x

Agata [3.3K]

We can actually see that the statements that are true are:

A. x = 1 is a solution.

C. x = –1 is a solution.

<h3>What is rational equation?</h3>

Rational equation is actually known as an equation that contains at least one fraction. The denominator and numerator are known to be polynomials.

We can see then that:

$\frac{4}{x + 6} + \frac{1}{ {x}^{2} } = \frac{x + 10}{ {x}^{3} + 6 {x}^{2} }$

It's clear that: x ≠ 0 and x ≠ -6.

Looking for the LCM of the left hand side, we will have:

$\frac{4}{x + 6} + \frac{1}{ {x}^{2} } = \frac{4 {x}^{2 } + (x + 6)}{(x + 6) {x}^{2} }$

So, we will see that left hand side and right hand side are equal.

$4 {x}^{2} + x + 6 = x + 10$

$4 {x}^{2} = 10 - 6$

$4 {x}^{2} = 4$

${x}^{2} = 1$

$x = 1$

or

$x = - 1$

So, we can see that options A and C are correct.

Learn more about rational equation on brainly.com/question/11611235

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2 years ago