Answer:
A = (2p + 9) (2p - 9)
B = (x - 9) (x - 4)
Step-by-step explanation:
For A : Rewrite 4p^2 as (2p)^2.
(2p)^2−81
Rewrite 81 as 9^2.
(2p)^2−9^2
Since both terms are perfect squares, factor using the difference of squares formula, a^2 − b^2 = ( a + b ) ( a − b ) where a = 2p and b = 9 .
(2p + 9) (2p − 9)
For B : Consider the form x^2 + bx + c . Find a pair of integers whose product is c and whose sum is b . In this case, whose product is 36 and whose sum is − 13 .
-9, -4
(x - 9) (x - 4)
I hope this helps.
Given:
x lies in the III quadrant.
To find:
The values of 
.
Solution:
It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.
We know that,
x lies in the III quadrant. So,
Now,
And,
We know that,
Therefore, the required values are 
.
0.002%. Just take 0.6/300 and input into a calculator.
<u>Answer:</u>
The system of equations are
x + y = 2600 …….equation (1)
and, 6x + 5y = 13700 ……equation (2)
<u>Explanation:</u>
Let x = amount of sales of phone;
y = amount of sales of computer
For phone, 6% of sales is 6% of x, or 6% * x = 0.06x.
Similarly for computer,
5% of y = 0.05y
Given the total sales; x + y = 2600
And commission; 0.06x + 0.05y = 137; or 6x + 5y = 13700
Therefore the system of equations are
x + y = 2600 …….equation (1)
6 x + 5 y = 13700 ……equation (2)
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