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omeli [17]
3 years ago
13

Let u=XY where X(-4, 6) and Y(8,3). What is 12 ul? 6/17 18 3/17 612

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

16) 1-3. 3-2. Find each product. 17) (-3X10) = -30. 18) (3)(-4) 2-12. 19) (-8)(5) = -40. 20) (7)(-9) =-63 ... 612-4)= 6(-2) = -12 se y. 4) x + x + y; use x = 1, and y= 1. 1+1 +1 3. 3. 3) (x - y) = 4; use x =-1, and y=-5 ... To earn more money her parents let some that were lost. How many did you begin her weed the garden for $9.80.

Step-by-step explanation:

faust18 [17]3 years ago
5 0

Answer:

A) 6 sqrt 17

Hope it helps.

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What is the total cost of a $12.49 item with a sales tax of 5%?
Ivan

Answer: $13.11

Step-by-step explanation:

hope this helps!

4 0
3 years ago
If f(x)= 3x + 4, then what is f(-2)
iren [92.7K]

Answer:

f ( - 2 ) = - 2

Step-by-step explanation:

Step 1:

f ( x ) = 3x + 4        Equation

Step 2:

f ( - 2 ) = 3 ( - 2 ) + 4     Input x value

Step 3:

f ( - 2 ) = - 6 + 4       Combine Like Terms

Answer:

f ( - 2 ) = - 2          Combine Like Terms

Hope This Helps :)

6 0
3 years ago
Which expression is equivalent to the following complex fraction? StartFraction 1 Over x EndFraction minus StartFraction 1 Over
Darina [25.2K]

Answer:

\frac{y-x}{x+y}

Step-by-step explanation:

We are given that fraction

\frac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}

We have to find the expression which is equivalent to given  fraction .

\frac{1}{x}-\frac{1}{y}=\frac{y-x}{xy}

\frac{1}{x}+\frac{1}{y}=\frac{x+y}{xy}

Substitute the values  then, we get

\frac{\frac{y-x}{xy}}{\frac{y+x}{xy}}

We know that

\frac{\frac{a}{b}}{\frac{x}{y}}=\frac{a}{b}\times \frac{y}{x}

Using the property then, we get

\frac{y-x}{xy}\times \frac{xy}{x+y}

\frac{y-x}{x+y}

This is required expression which is equivalent to given expression.

6 0
3 years ago
Read 2 more answers
HELP PLZ PICTURE^ Need it asap porfa
timurjin [86]

Answer:

it has one solution

Step-by-step explanation:

1.y=x-3

2. 3y-3x sub x-3 in place of y therefore

it can also be written as 3x-3x-9=9

if you add 9 to both sides 3x-3x-9+9=-9+9

0+0=0

3 0
3 years ago
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
3 years ago
Read 2 more answers
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