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omeli [17]
3 years ago
13

Let u=XY where X(-4, 6) and Y(8,3). What is 12 ul? 6/17 18 3/17 612

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

16) 1-3. 3-2. Find each product. 17) (-3X10) = -30. 18) (3)(-4) 2-12. 19) (-8)(5) = -40. 20) (7)(-9) =-63 ... 612-4)= 6(-2) = -12 se y. 4) x + x + y; use x = 1, and y= 1. 1+1 +1 3. 3. 3) (x - y) = 4; use x =-1, and y=-5 ... To earn more money her parents let some that were lost. How many did you begin her weed the garden for $9.80.

Step-by-step explanation:

faust18 [17]3 years ago
5 0

Answer:

A) 6 sqrt 17

Hope it helps.

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The function g(t) = - 16t2 + vt + h represents the height of an object, g, in feet, above the ground in relation to the time, t,
timurjin [86]

Answer:

g(t) = -16t^2+80t.

Step-by-step explanation:

We are given that v=80 and h=0 (because that's the ground), so substituting that into g(t) = -16t^2+vt+h gives g(t) = -16t^2+80t.

5 0
2 years ago
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Y=x^2-2x-1 and y=-3x+5 solved algebraically
eduard

Answer:

Step-by-step explanation:

y=x²-2x-1

and y=-3x+5

x²-2x-1=-3x+5

x²+x-6=0

x²+3x-2x-6=0

x(x+3)-2(x+3)=0

(x+3)(x-2)=0

x=-3,2

when x=-3

y=-3×-3+5=9+5=14

when x=2

y=-3×2+5=-6+5=-1

so solutions are (-3,14) and (2,-1)

3 0
3 years ago
Need help its hard sadly
Maslowich
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8 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
How to add and subtract positive and negative fractions
Dvinal [7]
Rules for adding: if the bases are the same you can add them, and subtracting happens in a fraction
5 0
3 years ago
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