Answer:

Explanation:
It is given that,
Mass of the clock, m = 108 kg
Force acting on it when it is in motion, 
After the clock is in motion, a horizontal force of 521 N keeps it moving with a constant velocity, F' = 521 N
It is assumed to find the coefficient of between the clock and the floor. The force of friction is given by :




So, the coefficient of static friction between the clock and the floor is 0.6. Hence, this is the required solution.
Answer:
0.47 N
Explanation:
q1 = 3.4 x 10^-6 C
q2 = 2 x 10^-6 C
d = 17.5 cm = 0.175 m
The electrostatic force is given by


F = 0.47 N
Thus, the force is 0.47 N.
D
Rocket engine igniting is chemical energy when he in turn makes it launch and move which is kinetic energy
Answer:

Explanation:
I was unable to submit this answer after typing it, so i create a document file that clearly shows and depicts all explanations for the question. OR
You can check the three picture slides i attached as well for the explanation.
The attached file for the document and the picture can be found below.
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