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Shalnov [3]
3 years ago
6

Which element has a complete valence electron shell?

Physics
2 answers:
ale4655 [162]3 years ago
7 0

Answer:

d) argon

.............

german3 years ago
3 0

Answer:

the answer is d.

Explanation:

Argon (Ar) has a complete valence electron shell.

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The combustion of fuel in a piston cylinder causes an internal energy change of –2836 kJ. The components surrounding the cylinde
ikadub [295]

Answer:

Explanation:

From first law of thermodynamics

Q = ΔE + W

Q is heat added , ΔE is increase in internal energy and W is work done.

Here Q = - 963.6 kJ  , - ve sign because head is absorbed

ΔE - 2836 kJ  , negative sign given ( gas cooled )

Putting these values in the equation above

- 963.6 = - 2836 + W

W = 2836 -  963.6 kJ

= 1872.4 kJ .

3 0
4 years ago
The photometer is a device that converts light to voltage which is read out by the digital multimeter (DMM). This is due to the
dimaraw [331]

Answer:

It converts light into electric current.

Explanation:

The first line of the description says that the photometer is a device that converts light to voltage. if the voltage can be measured then current flowing through it can be calculated by Ohms law V=IR.

<em>Hence the photometer converts light to electric current.</em>

The photometer is used to measure the strength of electromagnetic radiation falling on it and operate within the range of ultraviolet ,visible and infrared spectrum.

It converts light to electric current using photodiode (pn junction),photoresistor and photmultiplier.

 

8 0
3 years ago
In the figure, a proton is projected horizontally midway between two parallel plates that are separated by 0.50 cm, and are 5.60
noname [10]

a) Minimum speed of the proton: 6.05\cdot 10^6 m/s

b) Angle of the velocity: \theta=-5.1^{\circ}

Explanation:

a)

The proton experiences a vertical force due to the electric field, given by:

F=qE

where

q=1.6\cdot 10^{-19}C is the proton charge

E=610,000 N/C is the magnitude of the electric field

The vertical acceleration of the proton is therefore

a=\frac{qE}{m}

where

m=1.67\cdot 10^{-27}kg is its mass

Therefore, the vertical position of the proton at time t is

y(t)=\frac{1}{2}at^2=\frac{1}{2}\frac{qE}{m}t^2

where we assumed that the initial vertical velocity is zero (because the proton is fired horizontally) and the initial vertical position, halfway between the two plates, is the origin.

The horizontal motion of the proton instead is uniform, so the horizontal position is given by

x(t)=v_0 t

where v_0 is the initial speed. This equation can be rewritten as

t=\frac{x(t)}{v_0}

And substituting into the eq. for y,

y(t) = \frac{1}{2}\frac{qE}{m} \frac{x^2}{v_0^2}

Solving for the initial speed,

v_0 = \sqrt{\frac{qEx^2}{2my}}

The proton just misses one of the plate when

x = 5.60 cm = 0.056 m (length of the plates)

y = 0.25 cm = 0.0025 m (half the distance between the plates)

Therefore, we find the initial speed:

v=\sqrt{\frac{(1.6\cdot 10^{-19})(610,000)(0.056)^2}{2(1.67\cdot 10^{-27})(0.0025)}}=6.05\cdot 10^6 m/s

b)

In order to find the angle, we just need to analyze the horizontal and vertical component of the final velocity of the proton.

The horizontal velocity is constant so it is:

v_x = v_0 = 6.05\cdot 10^6 m/s

The vertical velocity is given by:

v_y^2 - u_y^2 = 2ay

where:

u_y=0 (initial vertical velocity is zero)

a=\frac{qE}{m} (acceleration)

y = 0.0025 m (vertical displacement)

Solving for v_y,

v_y = \sqrt{2ay}=\sqrt{2\frac{qEy}{m}}=5.4\cdot 10^5 m/s

Therefore, the final angle of the velocity with respect to the horizontal is:

\theta = tan^{-1}(\frac{v_y}{v_x})=tan^{-1}(\frac{5.4\cdot 10^5}{6.05\cdot 10^6})=5.1^{\circ}

And since the electric field is downward (the proton just misses the lower field), it means that the angle is below the horizontal:

\theta=-5.1^{\circ}

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

8 0
3 years ago
What is the value of acceleration that the car experiences
Anni [7]
Can u show the problem ?
Acceleration= the rate and change of an object also cars go fast so I think it would be positive acceleration
Hope I helped
7 0
4 years ago
When drawing a free-body diagram for an object on an inclined surface, which way does the force of gravity point? A. Straight do
babunello [35]
A- Straight Down

Remember wherever the object is, whether it is straight or inclined, gravitational pull will always act downwards.
8 0
4 years ago
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