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lys-0071 [83]
3 years ago
12

Your friend asks you to describe pseudoscience. You reply pseudoscience is

Physics
2 answers:
exis [7]3 years ago
6 0

your answer is 'D' something that resembles science but cannot be tested or proven using the scientific method

oksian1 [2.3K]3 years ago
5 0
The answer is most likely D. hope that helped 
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Explain why water boiling in a container stops<br>boiling momentarily when the lid is removed​
Dmitriy789 [7]

Answer:

It's because it tips over the threshold from nucleate boiling, which we can see, to convection boiling, which we can't. ... Even if the steam stayed in the pot, it would still stop boiling when you removed the heat. The steam and water in a liquid/vapour mixture are at the same temperature (100ºC).

Explanation:

8 0
3 years ago
A car moves at speed v across a bridge made in the shape of a circular arc of radius r. (a) Find an expression for the normal fo
inna [77]

Answer:

(a) FN = m (g - \frac{v^{2} }{r})

(b) vmin = 17.146 m/s

Explanation:

The radius of the arc is

r = 30m

The normal force acting on the car form the highest point is

FN = m (g - \frac{v^{2} }{r})

If the normal force become 0 we have

m (g - \frac{v^{2} }{r}) = 0

or

g - \frac{v^{2} }{r} = 0

This way, when FN = 0, then v = vmin, so

g - \frac{vmin^{2} }{r} = 0

vmin = \sqrt[.]{g*r} = \sqrt[.]{9.8 m/s^{2} * 30m } = 17.146 m/s

4 0
3 years ago
What is the net force on this object?​
Sergio039 [100]
200N

Explanation:
600N-400N = 200N
6 0
3 years ago
A 2.40 cm × 2.40 cm square loop of wire with resistance 1.20×10−2 Ω has one edge parallel to a long straight wire. The near edge
Norma-Jean [14]

Answer:

current in loops is 52.73 μA

Explanation:

given data

side of square a = b  = 2.40 cm = 0.024 m

resistance R = 1.20×10^−2 Ω

edge of the loop c  = 1.20 cm = 0.012 m

rate of current = 120 A/s

to find out

current in the loop

solution

we know current formula that is

current = voltage / resistance    .................a

so current = 1/R × d∅/dt

and we know here that

flux ∅ = ( μ×I×b / 2π ) × ln (a+c/c)    ...............b

so

d∅/dt = ( μ×b / 2π ) × ln (a+c/c) × dI/dt       ...........c

so from equation a we get here current

current = ( μ×b / 2πR ) × ln (a+c/c) × dI/dt

current = ( 4π×10^{-7}×0.024 / 2π(1.20×10^{-2}) × ln (0.024 + 0.012/0.012) × 120

solve it and we get current that is

current = 4 ×10^{-7}× 1.09861 × 120

current = 52.73 ×10^{-6}  A

so here current in loops is 52.73 μA

8 0
2 years ago
A constant net force acts on an object. which of the following best describes the object's motion?
Anton [14]
The object<span> is moving with a decreasing acceleration. The </span>object<span> is moving with </span>a constant<span> velocity.</span>
4 0
3 years ago
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