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4 years ago

Your friend asks you to describe pseudoscience. You reply pseudoscience is

Physics

2 answers:

exis [7]4 years ago

6 0

your answer is 'D' something that resembles science but cannot be tested or proven using the scientific method

oksian1 [2.3K]4 years ago

5 0

The answer is most likely D. hope that helped

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Buckets and a Pulley Two buckets of sand hang from opposite ends of a rope that passes over an ideal pulley. One bucket is full

marin [14]

Answer:

A: T = 120 N

B: T = 88.42 N

C: T = 70 N

Explanation:

Part A:

Since, the lighter bucket is supported by my had. So, the only unbalanced force in the system is the weight of heavier bucket. Hence, the tension in rope will be equal to the weight of heavier bucket.

T = 120 N

Part B:

This is the case where, two masses hang vertically on both sides of the pulley. To find the tension in such case we have the formula:

T = (2 m₁m₂g)/(m₁+m₂)

where,

m₁ = mass of heavier object = W₁/g = (120 N)/(9.8 m/s²) = 12.24 kg

m₁ = mass of lighter object = W₂/g = (70 N)/(9.8 m/s²) = 7.14 kg

g = 9.8 m/s²

Therefore,

T = [(2)(12.24 kg)(7.14 kg)(9.8 m/s²)]/(12.24kg + 7.14 kg)

T = 1713.6 N.kg/19.38 kg

T = 88.42 N

Part C:

Since, the heavier bucket is on ground. So, its weight is balanced by the normal reaction of the ground. The only unbalanced force in the system is the weight of lighter bucket. Hence, the tension in rope will be equal to the weight of lighter bucket.

T = 70 N

4 0

3 years ago

A model rocket is launched straight upward with an initial speed of 52.0 m/s. It accelerates with a constant upward acceleration

JulsSmile [24]

Explanation:

(a) After the engines stop, the rocket reaches a maximum height at which it will stop and begin to descend in free fall due to gravity.

(b) We must separate the motion into two parts, when the rocket's engines is on and when the rocket's engines is off.

First we must find the rocket speed when the engines stop:

$v_f^2=v_0^2+2ay_1\\v_f^2=(52\frac{m}{s})^2+2(1\frac{m}{s^2})(160m)\\v_f^2=3024\frac{m^2}{s^2}\\v_f=\sqrt{3024\frac{m^2}{s^2}}=54.99\frac{m}{s}$

This final speed is the initial speed in the second part of the motion, when engines stop until reach its maximun height. Therefore, in this part the final speed its zero and the value of g its negative, since decelerates the rocket:

$v_f^2=v_0^2+2gy_{2}\\y_{2}=\frac{v_f^2-v_0^2}{2g}\\y_{2}=\frac{0^2-(54.99\frac{m}{s})^2}{2(-9.8\frac{m}{s^2})}=154.28m$

So, the maximum height reached by the rocket is:

$h=y_1+y_2\\h=160m+154.28m=314.28m$

$v_f=v_0+at_1\\t_1=\frac{v_f-v_0}{a}\\t_1=\frac{54.99\frac{m}{s}-52\frac{m}{s}}{1\frac{m}{s^2}}\\t_1=2.99s$

And in the second part:

$t_2=\frac{v_f-v_0}{g}\\t_2=\frac{0-54.99\frac{m}{s}}{-9.8\frac{m}{s^2}}\\t_2=5.61s$

So, the time it takes to reach the maximum height is:

$t_3=t_1+t_2\\t_3=2.99s+5.61s=8.60s$

(d) We already know the time between the liftoff and the maximum height, we must find the rocket's time between the maximum height and the ground, therefore, is a free fall motion:

$v_f^2=v_0^2+2ay\\v_f^2=0^2+2(9.8\frac{m}{s^2})(314.28m)\\v_f=\sqrt{6159.888\frac{m^2}{s^2}}=78.48\frac{m}{s}$

$t_4=\frac{v_f-v_0}{g}\\t_4=\frac{78.48\frac{m}{s}-0}{9.8\frac{m}{s^2}}\\t_4=8.01s$

So, the total time is:

$t=t_3+t_4\\t=8.60s+8.01s\\t=16.61s$

7 0

4 years ago

A rock falls off a cliff. How fast is the rock traveling vertically two seconds later?

Vikentia [17]

The rock it traveling really, really fast.
It is hard to exactly determine how fast bc u need the height of the cliff and how big the rock is.
Hope this helps and can I get brainliest answer!

8 0

3 years ago

Which statement is TRUE about white light?

Olegator [25]

B: It contains all of the wavelengths of the visible light spectrum.
Hope this helps mate =)

6 0

3 years ago

Read 2 more answers

An object is approaching you while making a sound.

zvonat [6]

The pitch of the sound is perceived to be lower when an object is approaching you while making a sound.

<h3>What is sound?</h3>

Sound is a type of vibration capable of propagating in a suitable media (e.g., air or water).

The sound waves are called acoustic waves and they have a well-defined frequency and amplitude.

In conclusion, the pitch of the sound is perceived to be lower when an object is approaching you while making a sound.

Learn more about sound waves here:

brainly.com/question/1199084

#SPJ1

7 0

2 years ago