Answer:
Explanation:
The given data in the question is
Magnetic field : 
Turns : 
Length : 
So, number of turns per unit length :
If current is I , then magnetic field is given by
Also,
Insert the values
The current will be
Answer:
position 9.58 m
Explanation:
In impulse exercises and amount of movement, we always assume that the contact time is small,
I = Δp
With this expression we can calculate the final speed
I = m Vf - m Vo
Vf = (I + mVo) / m
Vf = (1.8 + 0.35 1.8) /0.35
Vf = 6.94 m / s
To calculate the acceleration of the ball we use Newton's second law, after finishing the impulse
∑ F = m a
fr = m a
a = fr / m
a = -0.26 / 0.35
a = -0.74 m/s²
A negative sign indicates that this acceleration is slowing the ball
Now we have speed and time acceleration, so we can use the kinematic equations to find the position at 1.5 s
X = Vo t + ½ to t²
In this case Vo is the speed with which the ball comes out after the impulse 6.94
X = 6.94 1.5 + ½ (-0.74) 1.522
X = 9.58 m
Decibels I believe? I’m not 100% sure
