Answer:
The box displacement after 6 seconds is 66 meters.
Explanation:
Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object (
), in meters, can be determined by the following expression:
(1)
Where:
- Initial velocity, in meters per second.
- Time, in seconds.
- Acceleration, in meters per square second.
If we know that 
, 
and 
, then the box displacement after 6 seconds is:
The box displacement after 6 seconds is 66 meters.
The correct answer is <span>A. By multiplying the change in mass by the square of the speed of light since the formula is expressed by </span>E = mc².
Answer:
For carbon 12
ΔV1 = 2265.31 V
ΔV2 = 362.5 V
For carbon 14
ΔV1 = 1941.7 V
ΔV2 = 310.67 V
Explanation:
The complete explanations are given in the attachment below. The formulae for the accelerating potential ΔV1 and ΔV2 are derived and the necessary parameters are substituted into the derived equations.
Explanation:
we first find acceleration by
V=u +at (v is the final velocity,u the initial velocity,a the acceleration and t the time taken)
v=25 m/s
u=0
t=3.6s
substituting we get
25=0 + a (3.6)
25=3.6a (diving both sides by 3.6 we get)
a=6.94 m/s^2
to find distance we use the equation v^2=u^2 + 2ad
25^2 =0^2 + 2 (6.94)do
625=13.88d (dividing both sides by 13.88 we get );
d=45m
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