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2 years ago

7

2x+10=12so x=??

e="\huge \dag \sf{Help \: me}" alt="\huge \dag \sf{Help \: me}" align="absmiddle" class="latex-formula">

2 answers:

almond37 [142]2 years ago

4 0

Answer:

$\boxed {\sf x=1}$

Step-by-step explanation:

$\sf 2x+10=12$

$\boxed{\mathrm{Subtract\:}10\mathrm{\:from\:both\:sides}}$

$\sf 2x+10-10=12-10$

$\sf 2x=2$

$\boxed{\mathrm{Divide\:both\:sides\:by\:}2}$

$\sf \cfrac{2x}{2}=\cfrac{2}{2}$

$\sf x=1$

$\boxed{\sf Hope\: it\:helps!}$

IRINA_888 [86]2 years ago

3 0

Answer:

$\sf\longmapsto\sf\boxed {x = 1}$

Step-by-step explanation:

$\sf\longmapsto \: 2x + 10 = 12$

$\sf\longmapsto \: \: 2x + 10 - 10 = 12 - 10$

$\sf\longmapsto \: 2x = 2$

$\sf\longmapsto \: \frac{2x}{2} = \frac{2}{2}$

$\sf\longmapsto \: x = 1$

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Answer:

flour = 11.5, sugar has to be equal to 2.75 pounds.

Step-by-step explanation:

your 2 inequalities are:

2x + 3y <= 40

y <= 2x + 6

the second equation can be shown as:

-2x + y <= 6

solve the equality portion of these 2 inequalities.

those are the following equations:

2x + 3y = 40

-2x + y = 6

add these equations together and solve for y to get

y = 11.5

that appears to be a break even point.

when y = 11.5, the first inequality is solved as follows:

2x + 3y <= 40

replace y with 11.5 and the inequality becomes:

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solve for x to get

x <= 2.75

when y = 11.5, the second inequality is solved as follows:

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replace y with 11.5 and the inequality becomes:

-2x + 11.5 <= 6

solve for x to get x >= 2.75

this indicates that, when y = 11.5, x has to be equal to 2.75.

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3 years ago

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Answer:

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[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

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for some c in the interval (-x, x)

In the particular case f

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<em> </em>

we have

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rusak2 [61]

Answer:

Please check the explanation!

Step-by-step explanation:

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Let us substitute all the table values

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