Answer:
- 3 (die)
- 4 (slips)
- 6 (spinner)
- 5 (ace)
Step-by-step explanation:
Josie rolls a six-sided die 18 times. What is the estimated number of times she rolls a two? 3 = (1/6)(18)
Slips of paper are numbered 1 through 10. If one slip is drawn and replaced 40 times, how many times should the slip with number 10 appear? 4 = (1/10)(40)
A spinner consists of 10 equal- sized spaces: 2 red, 3 black, and 5 white. If the spinner is spun 30 times, how many times should it land on a red space? 6 = (2/10)(30)
A card is picked from a standard deck of playing cards 65 times and replaced each time. About how many times would the card drawn be an ace? 5 = (4/52)(65)
_____
The probability of a given event is the number of ways it can occur divided by the number of possibilities. For example, a 2 is one of 6 numbers on a die, so we expect its probability of showing up to be 1/6. The expected number of times it will show up in 18 rolls of the die is (1/6)(18) = 3.
Step-by-step explanation:
Inflection points are where a function changes concavity (the second derivative changes signs). At x = 4, f"(x) goes from negative to positive, so that's an inflection point. However, at x = 8, we don't know if f"(x) changes signs or not. So we can't say that that's an inflection point.
Answer:
See below
Step-by-step explanation:
When we talk about the function 
, the domain and codomain are generally defaulted to be subsets of the Real set. Once 
and 
such that 
for 
. Therefore,
![\[\sqrt{\cdot}: \mathbb R_{\geq 0} \to \mathbb R_{\geq 0} \]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B%5Ccdot%7D%3A%20%5Cmathbb%20R_%7B%5Cgeq%200%7D%20%5Cto%20%5Cmathbb%20R_%7B%5Cgeq%200%7D%20%5C%5D)
![\[x \mapsto \sqrt{x}\]](https://tex.z-dn.net/?f=%5C%5Bx%20%5Cmapsto%20%5Csqrt%7Bx%7D%5C%5D)
But this table just shows the perfect square solutions.
Answer:
x = -1/3
x = 1
Step-by-step explanation:
Answer: C add 4 to both sides
I hope this helps you !
