Answer:
Step-by-step explanation: In graphing there are two letters x, and y also called X-axis and Y-axis. They are called ordered pairs. To graph on the bottom of the graph are numbers 1-10 or more, those are X. At the left is a straight line numbers 1-10 or more. Now to actually graph if you get an ordered pair lets say, 3,4. the number on the left is the X, and the number on the right is the Y. There is an end in the X-axis, and Y-axis. Start from there, you will always start at the bottom then the left. Start at the 0,0 go three times to left at the bottom, then at the left go up four times. when you get 3,4 add a dot. Then that's your answer. It pretty easy. Hope it helps you!
We need to find the other base also in order for us to find out what the area of this is.
Answer:
I think it is C because it keeps on going and it doesnt stop at 0
hope this :)
Step-by-step explanation:
Mark as brainllest if it helps
Answer:
a) 0.057
b) 0.5234
c) 0.4766
Step-by-step explanation:
a)
To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula
where
N = size of the sample.
So,
As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of 1.5811 and this would be your p-value.
We compute the area of the normal curve for values to the right of 1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.
So the p-value is
b)
Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.
We can compute the probability of such an error following the next steps:
<u>Step 1
</u>
Compute
So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.
<u>Step 2</u>
Compute the probability that your sample mean is less than 185.3711
So, <em>the probability of making a Type II error is 0.5234 = 52.34%
</em>
c)
<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is
1 - 0.5234 = 0.4766