The answer:93.75
I think recommend calculators online I’m sure I’m a little off
Answer:


And we can find the limits in order to consider values as significantly low and high like this:


Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
For this case we can consider a value to be significantly low if we have that the z score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is higher tor equal to 2.
For this case we have the mean and the deviation given:


And we can find the limits in order to consider values as significantly low and high like this:


The composite function combines the palm tree and the seed functions
The composite function is t(d) = 60d + 20
<h3>How to determine the composite functions</h3>
The functions are given as:
Number of palm trees: t(s) = 3s + 20
Number of seeds: s(d) = 20d
The composite function that represents the number of palm trees Carlos can expect to grow over a certain number of days is represented as:
t(s(d))
This is calculated as:
t(s(d)) = 3s(d) + 20
Substitute s(d) = 20d
t(s(d)) = 3 * 20d + 20
Evaluate the product
t(s(d)) = 60d + 20
Rewrite as:
t(d) = 60d + 20
Hence, the composite function is t(d) = 60d + 20
Read more about composite functions at:
brainly.com/question/10687170
The answer would be <span>y = 312.5x + 1564
hope this helped :)
alisa202</span>
C is the answer of the questions