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Answer:
No. See explanation below.
Step-by-step explanation:
Since the cards are being selected <u>without replacement,</u> every time we select a card, <u>the probability varies</u> (since there is one less card) and therefore, the probability doesn't remain the same for every trial and therefore, the probability of success changes for every trial.
It is because of this that this probability experiment doesn't represent a binomial experiment.
Answer:
No, h = (-23)/5
Step-by-step explanation:
Solve for h:
3 (4 - 6 h) - 7 h = 127
3 (4 - 6 h) = 12 - 18 h:
12 - 18 h - 7 h = 127
-18 h - 7 h = -25 h:
-25 h + 12 = 127
Subtract 12 from both sides:
(12 - 12) - 25 h = 127 - 12
12 - 12 = 0:
-25 h = 127 - 12
127 - 12 = 115:
-25 h = 115
Divide both sides of -25 h = 115 by -25:
(-25 h)/(-25) = 115/(-25)
(-25)/(-25) = 1:
h = 115/(-25)
The gcd of 115 and -25 is 5, so 115/(-25) = (5×23)/(5 (-5)) = 5/5×23/(-5) = 23/(-5):
h = 23/(-5)
Multiply numerator and denominator of 23/(-5) by -1:
Answer: h = (-23)/5
Answer:
By the Central Limit Theorem, it is approximately normal with mean 650 and standard deviation 4.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean of 650 and a standard deviation of 24.
This means that 
.
Sample of 36:
This means that 
What is the shape of the sampling distribution you would expect to produce?
By the Central Limit Theorem, it is approximately normal with mean 650 and standard deviation 4.
