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larisa [96]
3 years ago
12

The cost of 5 pounds of boudin is $26.What is the constant of proportionality that relates the cost in dollars,y, to the number

of pounds of boudin,x?
Mathematics
1 answer:
Ymorist [56]3 years ago
6 0

Given :

The cost of 5 pounds of boudin is $26.

To Find :

The constant of proportionality that relates the cost in dollars y, to the number of pounds of boudin x .

Solution :

Price per boudin in terms of x and y is :

P=\dfrac{y}{x}

Price per boudin by given data :

P=\dfrac{26}{5}

So,

\dfrac{y}{x}=\dfrac{26}{5}\\\\y = \dfrac{26}{5}x

Therefore, the constant of proportionality is \dfrac{26}{5}.

Hence, this is the required solution.

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Answer:

A. 90 sq. units


Step-by-step explanation:


6 0
3 years ago
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Tennis Replay In the year that this exercise was written, there were 879 challenges made to referee calls in professional tennis
tiny-mole [99]

Answer:

a. 0.0209 = 2.09% probability that among the 879 challenges, the number of overturned calls is exactly 231.

b. 231 is less than 2.5 standard deviations above the mean, which means that 231 overturned calls among 879 challenges is not a significantly high result.

Step-by-step explanation:

For each challenge, there are only two possible outcomes. Either it was overturned, or it was not. The probability of a challenge being overturned is independent of any other challenge. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Significantly high:

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

If a value is more than 2.5 standard deviations above the mean, this value is considered significantly high.

25% of the challenges are successfully upheld with the call overturned.

This means that p = 0.25

879 challenges

This meas that n = 879

a. If the 25% rate is correct, find the probability that among the 879 challenges, the number of overturned calls is exactly 231.

This is P(X = 231). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 231) = C_{879,231}.(0.25)^{231}.(0.75)^{648} = 0.0209

0.0209 = 2.09% probability that among the 879 challenges, the number of overturned calls is exactly 231.

b. If the 25% rate is correct, find the probability that among the 879 challenges, the number of overturned calls is 231 or more. If the 25% rate is correct, is 231 overturned calls among 879 challenges a result that is significantly high

The mean is:

E(X) = np = 879*0.25 = 219.75

The standard deviation is:

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{879*0.25*0.75} = 12.84

219.75 + 2.5*12.84 = 251.85 > 231

231 is less than 2.5 standard deviations above the mean, which means that 231 overturned calls among 879 challenges is not a significantly high result.

5 0
3 years ago
50 points if its correct with brainliest!! How many times smaller will a number become if you decrease it by 20%.
Likurg_2 [28]

Answer:

1/5 because 20% is equivalent to 20/100

Step-by-step explanation:

or 0.2 Thats what I got- sorry if I am wrong.

5 0
3 years ago
a circuit overloads at 1800 watts of electricity you plug a microwave oven that uses 1100 watts into the circuit write and solve
Bogdan [553]
Let w be the additional watts you can add on the circuit.

1100 + w < 1800 (write the inequality)
-1100 -1100 ( - 1100 from each side)

w < 700 (simplify)


ANSWER:
You can add up to 700 watts to the circuit, which means that you can also plug in the clock radio and the blender.


LOOK BACK:
You can check that your answer is correct by adding the numbers of watts used by the microwave oven, clock radio and blender.

1100 + 50 + 300 = 1450

The circuit will not overload because the total wattage is less than 1800 watts.
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Nataly [62]

Answer:

D. Part of the solution region includes a negative number of erasers purchased; therefore, not all solutions are viable for the given situation.

Step-by-step explanation:

I got it right on the practice

7 0
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