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vekshin1
3 years ago
6

Need help with my math hw

Mathematics
1 answer:
saw5 [17]3 years ago
4 0
The answer is B. Brainliest?
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What is equivalent to 1/40
Nimfa-mama [501]
2/80 is equivalent 
you can also just multiply the numerator and denominator to find out what else is equivalent.
5 0
2 years ago
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I need help with geometry
satela [25.4K]

Answer:

45 is the answer

Step-by-step explanation:

first you have to know the sum of interior angle of that pentagon (540)

then add the all angle.

148 + x + 112 + 90 + 3x + 10 = 540.

or, 360 + 4x = 540

or, 4x = 540 - 360

or, 4x = 180

or, x = 180/4

or, x = 45

hope it will help you☺✌

6 0
2 years ago
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Solve for x: 5x + 15 = 75
yuradex [85]

Answer:

x = 12

Step-by-step explanation:

5x + 15 = 75

      -15   -15

5x = 60

x = 12

3 0
2 years ago
How much money should be deposited today in an account that earns 6% compounded monthly so that it will accumulate to $1000000 (
aleksandr82 [10.1K]

Answer:

The principal investment required to get  a total amount of $ 1,000,000.00  from compound interest at a rate of 6% per year  compounded 12 times per year  over 45 years  is $ 67,659.17.

Step-by-step explanation:

Given

  • Accrued Amount A = $1000000
  • Interest rate r = 6% = 0.06
  • Time period t = 45 years
  • Compounded monthly n = 12

To determine:

  • Principle amount P = ?

Using the formula

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

P\:=\frac{A}{\left(1\:+\:\frac{r}{n}\right)^{nt}}

substituting A = 1000000, r =  0.06, t = 45, and n = 12

P\:=\frac{1000000}{\left(1\:+\:\frac{0.06}{12}\right)^{12\cdot 45}}\:

    =\frac{1000000}{1.005^{540}}

P = 67659.17 $

Therefore, the principal investment required to get  a total amount of $ 1,000,000.00  from compound interest at a rate of 6% per year  compounded 12 times per year  over 45 years  is $ 67,659.17.

7 0
3 years ago
The following polynomial can be factored using the techniques of this lesson x^2-18
Papessa [141]

Answer:

(x+3\sqrt{2})(x-3\sqrt{2})

Step-by-step explanation:

The given expression is x^2-18.

The technique that can be used to factor this polynomial is the difference of two squares.

We rewrite the two expressions as;

x^2-(\sqrt{18})^2

Recall that;

a^2-b^2=(a+b)(a-b)

x^2-(\sqrt{18})^2=(x+\sqrt{18})(x-\sqrt{18})

x^2-(\sqrt{18})^2=(x+3\sqrt{2})(x-3\sqrt{2})

8 0
3 years ago
Read 2 more answers
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