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Arada [10]
3 years ago
5

Find the matrix b from the question.

Mathematics
2 answers:
BigorU [14]3 years ago
3 0

Refer to the attachments...

Pavel [41]3 years ago
3 0

Answer:

\large{ \tt{❈ \: SEE \: THE \: ATTACHED \: PICTURE!} } :

ツHope I helped! ♡

☼Have a wonderful day / evening ! ☃

# StayInAndExplore ! ☂

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Please please help me out!!!!!!
Novosadov [1.4K]

Answer:

see explanation

Step-by-step explanation:

Inequalities of the type | x | > a, always have solutions of the form

x < - a or x > a

This can be extended to expressions, that is

14 - 5x < - 8 OR 14 - 5x > 8 ( subtract 14 from both sides of both inequalities )

- 5x < - 22 OR - 5x > - 6

Divide both sides by - 5 , reversing the inequality sign as a consequence

x > \frac{22}{5} OR x < \frac{6}{5}

That is the solution is

x < \frac{6}{5} OR x > \frac{22}{5}

5 0
3 years ago
Read 2 more answers
What is the answer to 8÷544
Stells [14]
8 ÷ 544 = 0.0147058824, 544 ÷ 8 = 68
3 0
3 years ago
Will mark brainliest for the correct answer!
romanna [79]

Part (a)

Focus on triangle PSQ. We have

angle P = 52

side PQ = 6.8

side SQ = 5.4

Use of the law of sines to determine angle S

sin(S)/PQ = sin(P)/SQ

sin(S)/(6.8) = sin(52)/(5.4)

sin(S) = 6.8*sin(52)/(5.4)

sin(S) = 0.99230983787513

S = arcsin(0.99230983787513)

S = 82.889762826274

Which is approximate

------------

Use this to find angle Q. Again we're only focusing on triangle PSQ.

P+S+Q = 180

Q = 180-P-S

Q = 180-52-82.889762826274

Q = 45.110237173726

Which is also approximate.

A more specific name for this angle is angle PQS, which will be useful later in part (b).

------------

Now find the area of triangle PSQ

area of triangle = 0.5*(side1)*(side2)*sin(included angle)

area of triangle PSQ = 0.5*(PQ)*(SQ)*sin(angle Q)

area of triangle PSQ = 0.5*(6.8)*(5.4)*sin(45.110237173726)

area of triangle PSQ = 13.0074347717966

------------

Next we'll use the fact that RS:SP is 2:1.

This means RS is twice as long as SP. Consequently, this means the area of triangle RSQ is twice that of the area of triangle PSQ. It might help to rotate the diagram so that line PSR is horizontal and Q is above this horizontal line.

We found

area of triangle PSQ = 13.0074347717966

So,

area of triangle RSQ = 2*(area of triangle PSQ)

area of triangle RSQ = 2*13.0074347717966

area of triangle RSQ = 26.0148695435932

------------

We're onto the last step. Add up the smaller triangular areas we found

area of triangle PQR = (area of triangle PSQ)+(area of triangle RSQ)

area of triangle PQR = (13.0074347717966)+(26.0148695435932)

area of triangle PQR = 39.0223043153899

------------

<h3>Answer: 39.0223043153899</h3>

This value is approximate. Round however you need to.

===========================================

Part (b)

Focus on triangle PSQ. Let's find the length of PS.

We'll use the value of angle Q to determine this length.

We'll use the law of sines

sin(Q)/(PS) = sin(P)/(SQ)

sin(45.110237173726)/(PS) = sin(52)/(5.4)

5.4*sin(45.110237173726) = PS*sin(52)

PS = 5.4*sin(45.110237173726)/sin(52)

PS = 4.8549034284642

Because RS is twice as long as PS, we know that

RS = 2*PS = 2*4.8549034284642 = 9.7098068569284

So,

PR = RS+PS

PR = 9.7098068569284 + 4.8549034284642

PR = 14.5647102853927

-------------

Next we use the law of cosines to find RQ

Focus on triangle PQR

c^2 = a^2 + b^2 - 2ab*cos(C)

(RQ)^2 = (PR)^2 + (PQ)^2 - 2(PR)*(PQ)*cos(P)

(RQ)^2 = (14.5647102853927)^2 + (6.8)^2 - 2(14.5647102853927)*(6.8)*cos(52)

(RQ)^2 = 136.420523798282

RQ = sqrt(136.420523798282)

RQ = 11.6799196828694

--------------

We'll use the law of sines to find angle R of triangle PQR

sin(R)/PQ = sin(P)/RQ

sin(R)/6.8 = sin(52)/11.6799196828694

sin(R) = 6.8*sin(52)/11.6799196828694

sin(R) = 0.4587765387107

R = arcsin(0.4587765387107)

R = 27.3081879220073

--------------

This leads to

P+Q+R = 180

Q = 180-P-R

Q = 180-52-27.3081879220073

Q = 100.691812077992

This is the measure of angle PQR

subtract off angle PQS found back in part (a)

angle SQR = (anglePQR) - (anglePQS)

angle SQR = (100.691812077992) - (45.110237173726)

angle SQR = 55.581574904266

--------------

<h3>Answer: 55.581574904266</h3>

This value is approximate. Round however you need to.

8 0
3 years ago
Following the lead of the National Wildlife Federation, the Department of the Interior of a South American country began to reco
chubhunter [2.5K]

Answer:

After 2009 the quality of the forests in this country improving.

Step-by-step explanation:

Consider the provided function.

f(t) = \frac{1}{3}t^3-\frac{5}{2}t^2 + 80

f'(t) = t^2-5t

Substitute f'(t)=0.

t^2-5t=0

t(t-5)=0

t=0\ or\ t=5

It is given that  (0 ≤ t ≤ 10)

The test interval are (0,5) and (5,10)

For (0 < t < 5) the value of f'(t)

For (5 < t < 10) the value of f'(t) >0

Hence, the function is increasing from (5,10).

t = 0 corresponds to 2004.

Therefore, after 2009 the quality of the forests in this country improving.

7 0
3 years ago
What are two consecutive even integers whose product is 1224?
Alex
You have your choice of two pairs of consecutive even integers:

-36  and  -34

OR

34  and  36 .
4 0
3 years ago
Read 2 more answers
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