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Arada [10]
3 years ago
5

Find the matrix b from the question.

Mathematics
2 answers:
BigorU [14]3 years ago
3 0

Refer to the attachments...

Pavel [41]3 years ago
3 0

Answer:

\large{ \tt{❈ \: SEE \: THE \: ATTACHED \: PICTURE!} } :

ツHope I helped! ♡

☼Have a wonderful day / evening ! ☃

# StayInAndExplore ! ☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

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The length of the rectangle below is (2x-3) and the width is (x+7). Find the area of the rectangle in terms of x.
Alex777 [14]

Answer:

area = 2x² - 17x - 21

Step-by-step explanation:

Area of the rectangle is:

area = (width*length)

area = (x+7)*(2x-3)

        = x*2x + x*-3 + 7*2x + 7*-3

        = 2x² - 3x - 14x - 21

        = 2x² - 17x - 21

4 0
3 years ago
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
2 years ago
​
DedPeter [7]

Answer:

The solution is (3/8, -7/8).

Step-by-step explanation:

y = −5x + 1

y = 3x − 2

Since  the 2 expressions in x are both equal to y :

−5x + 1  = 3x - 2

-5x - 3x = -2 - 1

-8x = -3

x = 3/8.

So y = 3x - 2

= 3(3/8) - 2

= 9/8 - 2 = -7/8.

6 0
3 years ago
The area of a compact disc is 78.53 square centimeters. What is the radius of the disc? Use pi = 3.14
Tom [10]

Answer:

r = 5 cm

Step-by-step explanation:

A = πr²

78.53 = (3.14)r²

divide by 3.14

25 = r²

r = ±5

r = 5

5 0
3 years ago
A circle has a radius of 2 feet. What is the length of the arc subtended by a 15 degree central angle?
kari74 [83]

Answer:

Step-by-step explanation:

length = Pi.radius.15degree/180degree

= Pi.2.15/180 = about 0,5 feet

7 0
3 years ago
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