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natali 33 [55]
3 years ago
13

How many solutions does the system have?

Mathematics
1 answer:
Mrac [35]3 years ago
3 0

Answer:

A Exactly one solution

Step-by-step explanation:

\left \{ {{6x-3y=9} \atop {6x+y=9}} \right.\\\\\left \{ {{6x-3y=9} \atop {-6x-y=-9}} \right\\\\Then, \\\\-4y=0\\\\\\ y=0\\\\

Putting y=0 at second equation, we have

-6x=-9\\\\x=\frac{9}{6} =\frac{3}{2}

The unique solution is (\frac{3}{2} , 0)

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I need help, please and thank you.
Arturiano [62]

Answer:

Step-by-step explanation:

/lkEVDBUI;KJ/ LRVNIACS'J

doing this for the points hahahahaha

5 0
3 years ago
Use completing the aquare to solve for x in the equation (x+7)(x-9)=25​
Tema [17]

Answer:

x = 1 + sqrt(89) or x = 1 - sqrt(89)

Step-by-step explanation:

Solve for x:

(x - 9) (x + 7) = 25

Expand out terms of the left hand side:

x^2 - 2 x - 63 = 25

Add 63 to both sides:

x^2 - 2 x = 88

Add 1 to both sides:

x^2 - 2 x + 1 = 89

Write the left hand side as a square:

(x - 1)^2 = 89

Take the square root of both sides:

x - 1 = sqrt(89) or x - 1 = -sqrt(89)

Add 1 to both sides:

x = 1 + sqrt(89) or x - 1 = -sqrt(89)

Add 1 to both sides:

Answer: x = 1 + sqrt(89) or x = 1 - sqrt(89)

7 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
If the can of dogfood holds 8 ounces and the bag of dogfood holds 30 times the volume , how many pounds of dogfood does the bag
Maru [420]

Answer:

15 pound in a bag

Step-by-step explanation:

one can= 8 oz

one bag= 30 times the amount in a can

               8 oz x 30 =  240 oz in a bag

Question asked how many pound is in one bag of dog food:

We know that 16 oz = 1 pound

                       240 oz = x pound

To find x pound we divide 240 oz by 16 oz-->

240 oz/ 16 oz = 15 pound

7 0
3 years ago
How many more monthly payments are made for a 5 year loan than a 2 year loan​
Mekhanik [1.2K]

Answer:

36 more loans

Step-by-step explanation:

4 0
3 years ago
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