Answer:
Step-by-step explanation:
2x^2-10x+7 A=1, B=-10. C=7
-(-10)±√-10^2-4(1)(7)
------------------------------
2(1)
10±√100-28
----------------
2
10±√72
-----------
2
<u>10±8.485281374</u>
2
<u>10+8.485281374 </u>=9.24
2
<u>10-8.485281374</u> =0.76
2
Answer:
11196.15 km
Step-by-step explanation:
Consider the attached diagram
If the Airplane is at point A and the floating debris at point C, we want to determine the horizontal distance |AB| before they fly over it.
Using trigonometry

Cross multiply
|AB|X Tan 15 =3000
|AB| =
=11196.15 km
Therefore, the horizontal distance |AB| before they fly over it is 11196.15 km
Answer:

Step-by-step explanation:
To write the quadratic in standard form, begin by writing it in vertex form

Where (h,k) is the vertex of the parabola.
Here the vertex is (-3,-2). Substitute and write:

To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.

The vertex form of the equation is
.
To write in standard form, convert vertex form through the distributive property.

Angle BDC is given as 38° but not drawn in the figure. Amateurs.
We calculate angle DBC
DBC = 180° - 96° - 38° = 180° - 134°
We won't bother subtracting because we're really after
angle ABD = 180° - DBC = 134°
Now we have a Law of Cosines situation,
AD² = AB² + BD² - 2(AB)(BD) cos ABD
AD = √( 5.8² + 27.3² - 2(5.8)(27.3) cos 134°)
AD ≈ 31.61 m
Answer: 31.6 m