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soldi70 [24.7K]
3 years ago
10

Please help! Consider matrices A, B, and C. Which matrix represents (A-B)-C?

Mathematics
1 answer:
Firdavs [7]3 years ago
8 0

Answer:

B.) I cant insert a 2x2 matric but the [5 7

                                                             7 4]  matrix is correct

                                                             

Step-by-step explanation:

I got a 5/5 on the test so I know that B is the correct answer

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7x - 3y = 31<br> 7x + y = -1<br><br><br> Please solve x and y
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(1, -8)

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Step-by-step explanation:

7x-3y= 31

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4 years ago
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3 years ago
1. It is a set of all points in a plane with same distance from a certain point.
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Step-by-step explanation:

5 0
3 years ago
a school netball team won ten matches , lost four and drew 1/8 of the total played . how many matches were drawn and what fracti
defon

The school net ball team drew 2 matches. The team won \frac{5}{8} of total matches played

<h3><u>Solution:</u></h3>

Given, A school netball team won ten matches, lost four and drew \frac{1}{8} of the total played

Let the total number of matches played be "n"

Number of matches drawn = \frac{1}{8} of n

<em>Total matches played = number of won matches + number of lost matches + number of drawn matches</em>

\begin{array}{l}{n=10+4+\frac{1}{8} n} \\\\ {n-\frac{1}{8} n=10+4}\end{array}

Taking "n" as common from left hand side,

\begin{array}{l}{\mathrm{n}\left(1-\frac{1}{8}\right)=14} \\\\ {\mathrm{n} \times \frac{8-1}{8} \quad 14} \\\\ {\mathrm{n} \times \frac{7}{8}=14} \\\\ {\mathrm{n}=16}\end{array}

So, they played 16 matches in total

Number of matches drawn = \frac{1}{8} of n = \frac{1}{8} \times 16 = 2\text { Fraction of won matches }=\frac{\text { number of matches won }}{\text { number of matches played }}=\frac{10}{16}=\frac{5}{8}

\text { Hence, the team drew } 2 \text { matches and won } \frac{5}{8} \text { of total played matches. }

3 0
3 years ago
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