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soldi70 [24.7K]
3 years ago
10

Please help! Consider matrices A, B, and C. Which matrix represents (A-B)-C?

Mathematics
1 answer:
Firdavs [7]3 years ago
8 0

Answer:

B.) I cant insert a 2x2 matric but the [5 7

                                                             7 4]  matrix is correct

                                                             

Step-by-step explanation:

I got a 5/5 on the test so I know that B is the correct answer

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Local extreme Value for each of the Following A) F(x)=x^² - 4x² +5​
kobusy [5.1K]

Answer:

max{x²-4x²+5} = 5 at x = 0

Step-by-step explanation:

1. Find the critical numbers by finding the first derivative of f(x), set it to 0 and solve for x.

f'(x)=0

We get:

f(x) = -3x^2+5\\f'(x) = -6x\\-6x = 0\\x = 0

So the critical number is x = 0.

2. Evaluate the first derivative by plugging in the critical number and see if the derivative is positive or negative on both sides:

f'(x) is positive when the x < 0 (for example: -6*(-1)=+)

f'(x) is negative when the x > 0 (for example: -6*(1)=-)

Therefore, you have a local maximum.

Now just get the Y value by plugging in the critical number in the original function. f(0)=5

local maximum is (0,5)

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2 years ago
PLEASE HELP ME!! I WILL GIVE YOU BRAINLIEST AND 50 POINTS!! AND DON'T JUST PUT YES, NO AND THEN NUMBERS, *USE COMPLETE SENTENCES
viva [34]

Answer:

John Muir

John Muir was an American naturalist born in Scotland on April 21, 1838. Step-by-step explanation:

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3 years ago
1. What number will make this expression a perfect square trinomial? Show your work. x2 - 6x +​
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Step-by-step explanation:

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Read 2 more answers
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

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C, E, and F have 50 50 chance
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