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3 years ago

Verify the following identity: sinx+cosx×cotx=cscx

1 answer:

3 0

Left Hand Side :
sin
x
+
cos
x
cot
x
We know that
cot
x
=
cos
x
sin
x
Therefore
sin
x
+
cos
x
cot
x
=
sin
x
+
cos
x
⋅
(
cos
x
sin
x
)
=
sin
x
+
cos
2
x
sin
x
=
sin
2
x
+
cos
2
x
sin
x
(We know the Trigonometric Identity
sin
2
x
+
cos
2
x
=
1
)
=
1
sin
x
=
csc
x
(Because Cosecant is the reciprocal of Sine)
Hence Proved.

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3 years ago

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3 years ago

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A bag contains 28 blue marbles and 12 red marbles. If Milton removes two marbles without replacing them, what is the probability

Daniel [21]

The probability the first marble will be blue is 28/40
The probability the second marble will be red is 12/39
The reason is because 28 + 12 = 40, so this makes the denominator for our first outcome, but then a marble is removed making our denominator 39 because 40-1 = 39.

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3 years ago

A construction crew is building a two story house, but they have not built the staircase between the floor yet. The height of th

Naya [18.7K]

Answer:

13.4feet

Step-by-step explanation:

The set up forms a right triangle.

Given

Height of the staircase h = 12 feet

Base of the stairs b = 6feet

Required

Length of the ramp l

Using the pythagoras theorem

l² = h² + b²

l² = 12²+6²

l² = 144 + 36

l² = 180

l = √180

l = 13.42 feet

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3 years ago

Rabies is a viral disease of mammals transmitted through the bite of a rabid animal. The virus infects the central nervous syste

lisabon 2012 [21]

Answer:

(a) The value of x is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

Step-by-step explanation:

Denote the events as follows:

R = reported case of rabies is a raccoon

F = reported case of rabies is a fox

B = reported case of rabies is a bat

O = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = x.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, $\sum P(X)=1$

Compute the value of x as follows:

$\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30$

Thus, the value of x is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

$P(A^{c})=1-P(A)$

Compute the probability that a reported case of rabies is not a raccoon as follows:

$P(R^{c})=1-P(R)\\=1-0.55\\=0.45$

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

$P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15$

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

4 0

3 years ago

Verify the following identity: sinx+cosx×cotx=cscx​

Verify the following identity: sinx+cosx×cotx=cscx