Answer:
Every group of 6 people has at least two uniform 3-person groups.
Step-by-step explanation:
Denote the 6-people by 6-vertices and draw a blue edge between 2-edges. If the two persons representing the vertices are friends. Otherwise, draw a red edge. This gives rise to a colored graph K6, edges arecolored with either blue or red.
There can exist at most 36 mips. so, multicolor triangles can exist at most 36/2 = 18 multicolor triangles.
If there are 20-triangle in graph. Therefore, every graph of 6-people has at least two uniform 3-person groups.
Step-by-step explanation:
135 = <2 + 86 [exterior angle of triangle is equal to the sum of its oppsite two interior angles]
or, <2 = 135 - 86
so, <2 = 49°
<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
Answer:
3r(to the secondpower) + 20r - 32
Step-by-step explanation:
