Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form
, where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

Let us solve for n.





We can also write next terms of our sequence as:

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
Answer:
C- all numbers less than 13.
Why these are incorrect:
A- If it was "less than or equal to" the sign would have to be "≤"
B- If it was 'greater than or equal to" the sign would have to be "≥"
D- If it was "greater than" the sign would have to be ">"
They're all d).
1) 28>24=10+14
2) Either 96/8=? or 8*?=96 describe the problem, ? being the number of chairs (the blank square in the answers). Of the two only the first appears in the options.
3) This question is ambiguous: if someone went both days, we could say the total number of people who went to the Saturday and Sunday games would be less than 3271+5844=9115. But who wrote the question likely wanted you to just do the sum between the two numbers, so of all options d is likely what they want you to choose.