1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s2008m [1.1K]
3 years ago
13

4. What is the result of 0.24 0.01? * O A. 24 O B.2.4 O c.0.24 O D.0.024​

Mathematics
1 answer:
Licemer1 [7]3 years ago
7 0

Answer:

The result of 0.24 and 0.01 is 0.0024.

Step-by-step explanation:

You would take the 0.24 and move left two spaces and then multiply by 1 and thats the answer.

You might be interested in
Connor believed that he did not do well in his ABC physics test. All ABC physics test scores are normally distributed with a mea
jenyasd209 [6]

Answer:

Yes! he passed

Step-by-step explanation:

8 0
3 years ago
Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16
IrinaK [193]

Answer:

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form a_n=a_1+(n-1)d, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

n =  Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

1

Let us solve for n.

1

1

1\cdot \frac{16}{3}

5.333

n>5.333

We can also write next terms of our sequence as:

\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

7 0
3 years ago
1/7 x g = 1<br><br><br> what's g
True [87]
G
=
7
x
That’s the answer
4 0
3 years ago
Read 2 more answers
Only need question 2
Elza [17]

Answer:

C- all numbers less than 13.

Why these are incorrect:

A- If it was "less than or equal to" the sign would have to be "≤"

B- If it was 'greater than or equal to" the sign would have to be "≥"

D- If it was "greater than" the sign would have to be ">"

4 0
3 years ago
Awnser please please
astraxan [27]
They're all d).

1) 28>24=10+14

2) Either 96/8=? or 8*?=96 describe the problem, ? being the number of chairs (the blank square in the answers). Of the two only the first appears in the options.

3) This question is ambiguous: if someone went both days, we could say the total number of people who went to the Saturday and Sunday games would be less than 3271+5844=9115. But who wrote the question likely wanted you to just do the sum between the two numbers, so of all options d is likely what they want you to choose.

6 0
3 years ago
Other questions:
  • Please help. urgent!
    14·1 answer
  • If Jay ran 1 mile in 10 minutes on Monday, 2 miles in 20 minutes on Tuesday,
    11·1 answer
  • The domain of startfraction f over g endfraction f g consists of numbers x for which g left parenthesis x right parenthesisg(x)
    12·1 answer
  • In the function f(×)=4-ײ,find f(-3)​
    8·2 answers
  • Which ordered pair is a solution to the equation y=-2/5x+9
    12·1 answer
  • The area of a rectangle with a height of 2 and a width of 5x^2-2x+3
    10·2 answers
  • Find the probability of a choosing a student that is taking a foreign language, given that the student is playing a sport using
    5·1 answer
  • Evaluate the function g(t)=23t, when t = 30.
    7·1 answer
  • Rectangle PQRS with vertices P(- 6, 9) , Q(3, 6); R(0, - 9) and S(- 9, - 6)
    7·1 answer
  • What is 35x 1 ? OMG this is such a hard question!! first one to answer will get a brainliest!!!
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!