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myrzilka [38]
3 years ago
12

Quadratic Equations and Functions - Part 2

Mathematics
2 answers:
ryzh [129]3 years ago
7 0

When the ball hits the ground, the height is 0. Substitute 0 for

h

.

h

=

−

16

t

2

−

10

t

+

200

0

=

−

16

t

2

−

10

t

+

200

−

16

t

2

−

10

t

+

200

=

0

This equation is difficult to solve by factoring or by completing the square, so solve it by applying the Quadratic Formula,

x

=

−

b

±

√

b

2

−

4

a

c

2

a

. In this case, the variable is

t

rather than

x

.

a

=

−

16

,

b

=

−

10

, and

c

=

200

.

t

=

−

(

−

10

)

±

√

(

−

10

)

2

−

4

(

−

16

)

(

200

)

2

(

−

16

)

Simplify. Be very careful with the signs.

t

=

10

±

√

100

+

12800

−

32

=

10

±

√

12900

−

32

Use a calculator to find both roots.

t

is approximately

−

3.86

or

3.24

.

Consider the roots logically. One solution,

−

3.86

, cannot be the time because it is a negative number. The other solution,

3.24

seconds, must be when the ball hits the ground.

Answer

The ball hits the ground approximately

3.24

seconds after being thrown.

exis [7]3 years ago
4 0

Answer:

See below

Step-by-step explanation:

<u>Given function</u>

  • h(t) = 5 + 98t – 4.9t²
<h3>Part A</h3>

<u>Filling in the table using the function, substitute t for each line:</u>

<u>time   |    elevation</u>

<u>0        |   5              </u>

<u>5        |   372.5       </u>

<u>10       |   495         </u>    

<u>15       |   372.5      </u>

<u>20      |   5             </u>

<h3>Part B</h3>

The graph is attached

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Molly took part in a math quiz and scored 55 points on 30 questions. Of the questions, there were 3-point word problems, 2-point
seropon [69]

Answer:

3\ point\ word = 5

2\ point\ word = 15

1\ point\ word = 10

Step-by-step explanation:

Given

Represent

3-point word with T;

2-point with U and

1-point with V

U = 5 + V --- (1)

If total questions is 30, then

T + U + V = 30 --- (2)

If total points is 55, then

3T + 2U + V = 55 --- (3)

Substitute 5 + V for U in (2) and (3)

T + U + V = 30 --- (2)

T + 5 + V + V = 30

T + 5 + 2V = 30

T + 2V = 25 ---- (4)

3T + 2U + V = 55 --- (3)

3T + 2(5 + V) + V = 55

3T + 10 + 2V + V = 55

3T + 10 + 3V = 55

3T  + 3V = 55 - 10

3T  + 3V = 45

Divide through by 3

T + V = 15 ---- (5)

Subtract (5) from (4)

(T + 2V = 25 )- (T + V = 15)

T - T + 2V - V = 25 - 15

V = 10

Recall that:

U = 5 + V

U = 5 + 10

U = 15

Substitute 10 for V in (5)

T + V = 15

T + 10 = 15

T = 5

3 0
3 years ago
3. If 30 is 50% of a value, what is that value?
Anvisha [2.4K]
.50 × N = 30
Divide both sides by .50
N = 60.
5 0
3 years ago
The diagram below shows the construction of the bisector of ∠abc. which statement is not true?
Ksenya-84 [330]

Answer:

c)\overline{AC}=2\overline{AB}

Step-by-step explanation:

<u>Retrieved Information:</u>

Which statement is not true?

a) a)\overline{AC}=\overline{CB}\\b)\overline{CB}=\frac{1}{2}\overline{AB} \\c)\overline{AC}=2\overline{AB}\\d)\overline{AC}+\overline{CB}=\overline{AB}

b) Check the graph below

1) To bisect is to equally divide an angle or a line segment, into two equal parts. The bisector of AC divides the line segment AC in its midpoint, so AC≅CB, therefore AC=CB. In addition to this, this is equivalent to say that CB is = 1/2AB.

Finally, this is also true that AC+CB=AB.

2) Clearly AC is not equal to 2AB since AC=CB is = 1/2AB then it is false.

c)\overline{AC}=2\overline{AB}\:FALSE

6 0
3 years ago
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