3 years ago

Find the mean of the following data set. 42, 45, 58, 63 42 47 52

Mathematics

1 answer:

igomit [66]3 years ago

6 0

52 i believe.

42 + 45 + 58 + 63 = 208
208 / 4 = 52

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Write a equation of a line perpendicular to the line below in point-slope from that passes through the point (-2,6)

STatiana [176]

Answer:

Option 1: $y-6=-4(x+2)$

Step-by-step explanation:

Find the slope of the perpendicular line by finding the negative reciprocal of the original slope. (Negative reciprocal = flip upside down and add a negative). So we get -4 for the perpendicular slope.

Next, we know the point (-2,6) is on the line, so we can get x=-2 and y=6.

Plug this into point-slope form: $y_{1}-y_{2}=m(x_{1}=x_{2})$

$y_{1} - (6)=-4(x_{1}-(-2))$

$y-6=-4(x+2)$

6 0

2 years ago

How do you solve :<br><br><img src="https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="Tex

Neporo4naja [7]

$x^2=\dfrac{2}{3}\to x=\pm\sqrt{\dfrac{2}{3}}\\\\x=-\dfrac{\sqrt{2}}{\sqrt3}\ \vee\ x=\dfrac{\sqrt2}{\sqrt3}\\\\x=-\dfrac{\sqrt2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}\ \vee\ x=\dfrac{\sqrt2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}\\\\\boxed{x=-\dfrac{\sqrt6}{3}\ \vee\ x=\dfrac{\sqrt6}{3}}$