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3 years ago

Divide 310AED among A B C in the ratio 2:3:5

Mathematics

2 answers:

Zarrin [17]3 years ago

7 0

Answer:

A=62 B=93 C=155

Explanation

You first add all the ratios and get 10.

To get the first ratio you write down 2/10 ×310/1 then you will get 31 ×2 you get 62

For you to get the second ratio now you do the same as the first ratio 3/10×310/1= 31 ×3 you get 93.

You do the same for the third ratio.

5/10×310/1= 31×5 you will get 155.

This is how you solve it. Sometimes you could get 4 or 5 ratios but what does not change us how you work the answer. This applies to every ratios.

Shkiper50 [21]3 years ago

5 0

Answer:A=62AED B=93 C=155

Step-by-step explanation:

You add all of the numbers to split between (2,3,5) you get 10

then you divided 310 by 10 which is 31

then you times 2 by 31=62 (a)

3x31=93 (b)

5x31=155 (c)

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Find the first four terms of the sequence An=2a n-1,where a1=3

yKpoI14uk [10]

The first four terms of the sequence are 3 , 6 , 12 , 24

Step-by-step explanation:

We need to find the first four terms of the sequence $a_{n}=2a_{n-1}$

where $a_{1}=3$ to find them do that

Substitute n by 2 in the rule to find $a_{2}$
Substitute n by 3 in the rule to find $a_{3}$
Substitute n by 4 in the rule to find $a_{4}$

∵ $a_{n}=2a_{n-1}$

- Substitute n by 2 to find the 2nd term

∴ $a_{2}=2a_{2-1}$

∴ $a_{2}=2a_{1}$

∵ $a_{1}=3$

∴ $a_{2}=2(3)$

∴ $a_{2}=6$

- Substitute n by 3 to find the 3rd term

∴ $a_{3}=2a_{3-1}$

∴ $a_{3}=2a_{2}$

∵ $a_{2}=6$

∴ $a_{3}=2(6)$

∴ $a_{3}=12$

- Substitute n by 4 to find the 4th term

∴ $a_{4}=2a_{4-1}$

∴ $a_{4}=2a_{3}$

∵ $a_{3}=12$

∴ $a_{4}=2(12)$

∴ $a_{4}=24$

The first four terms of the sequence are 3 , 6 , 12 , 24

Learn more:

You can learn more about the sequences in brainly.com/question/1522572

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3 years ago

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kozerog [31]

Answer: compare the relative strength of coefficients.

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Aleksandr [31]

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Source:
http://www.1728.org/compint3.htm

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Answer:

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