Answer:
The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction
Step-by-step explanation:
- For a constant acceleration:
, where 
is the final velocity in a direction after the acceleration is applied, 
is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied. - <em>Then for the x direction</em> it is known that the initial velocity is
5320 m/s, the acceleration (the applied by the engine) in x direction is 
1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: 
- In the same fashion, <em>for the y direction</em>, the initial velocity is
0 m/s, the acceleration in y direction is 
7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: 
Adjacent angles are angles with a common side and vertex, linear pairs are adjacent angles that are supplementary, and vertical angles are angles made by the same two lines but on opposite sides.
For the first one, 5 and 6 clearly do not share a side but they are made up by the same 2 lines and are opposite of each other, making them vertical.
For the next one, since the angles only share 1 line (and not a side) they can't be any of the above.
$1040.00
______________________________________________
Raphael paid $624
624/.60= 1040.00
Answer:
Solution point is (-1,-9)
Step-by-step explanation:
Put the value of y in the first equation into the second equation.
- 2x + 5(3x - 5) = - 42 Remove the brackets on the left
- 2x + 15x - 25 = - 42 Combine like terms on the left
- 17x - 25 = - 42 Add 25 to both sides
- 17x - 25 + 25 = - 42 + 25 Do the addition
- 17x = - 17 Divide by 17
- 17x/17 = -17/17 Do the division
- x = - 1
=======
Solve for y
- y = 3x - 6
- x = -1
- y = 3(-1) - 6
- y = -3 - 6
- y = - 9
