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IrinaK [193]
3 years ago
10

Simplify the expression using the order of operations.

Mathematics
2 answers:
Brrunno [24]3 years ago
8 0

Answer:

72

Step-by-step explanation:

7x 6 + 6 x 5

42 + 6 x 5

42 + 30

72

marin [14]3 years ago
8 0

Answer:

72

Step-by-step explanation:

7x6= 42

6x5 =30

42+30=72

or

take 6 out

6(7+5)

6(12)

72

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The amazon rainforest covered 6.42 million square kilometers in 1994. In 2014, it covered 50/59 as much. Which is closest to the
USPshnik [31]

the answer is b, just divide 50 by 59 and multiply that sum to 6.4

3 0
3 years ago
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44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
What are the zeros of f(x)=(x+5)(x-9)?
klemol [59]

Answer:

x= -5

x= 9

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The masses mi are located at the points Pi. Find the moments Mx and My and the center of mass of the system. m1 = 4, m2 = 3, m3
viva [34]

Answer:

M_x= 8

M_y = 6

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

Step-by-step explanation:

Center of mass: Center of mass of an object is a point on the object. Center of mass is the average position of the system.

Center of mass of a triangle is the centriod of a triangle.

Given that m₁= 4, m₂=3, m₃=3 and the points are P₁(2,-3), P₂(-3,1) and P₃(3,5)

M_x = ∑(mass × x-co-ordinate)

M_y = ∑(mass × y-co-ordinate)

Therefore  

M_x = (4×2)+{3×(-3)}+(3×3)

     =8

M_y = {4×(-3)}+{3×1}+(3×5)

    =6

The x co-ordinate of the center of mass is the ratio of M_x to the total mass.

The y co-ordinate of the center of mass is the ratio of M_y to the total mass.

Total mass (m) = m₁+ m₂+ m₃

                        = 4+3+3

                        =10

The x co-ordinate of the center of mass is \frac {8}{10} = \frac {4}{5}

The y co-ordinate of the center of mass is \frac{6}{10}=\frac{3}{5}

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

4 0
3 years ago
Please help me with this problem, please
Harman [31]

Answer:

sin(x) = 5/13

cos(y) = 5/12

Therefore, sin(x) = cos(y)

Step-by-step explanation:

Trig ratios:

sin(\theta)=\dfrac{O}{H}\\\\\\cos(\theta)=\dfrac{A}{H}\\\\\\tan(\theta)=\dfrac{O}{A}

where \theta is the angle, O is the measure of the side opposite the angle, A is the measure of the side adjacent to the angle and H is the hypotenuse, of a right triangle

We have been given the measures of the two legs, so we can find the measure of the hypotenuse by using Pythagoras' Theorem a^2+b^2=c^2

(where a and b are the legs and c is the hypotenuse of a right triangle)

\implies 5^2+12^2=c"\\\\\implies 169=c^2\\\\\implies c=\sqrt{169}\\\\ \implies c=13

Now we can use the trig ratios:

\implies sin(x)=\dfrac{5}{13}

\implies cos(y)=\dfrac{5}{13}

Therefore, sin(x) = cos(y)

8 0
2 years ago
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