Answer:
The molarity of this solution is 2.26 M (option D)
Explanation:
Step 1: Data given
Mass % = 17%
Molar mass of CH3COONa = 82.0 g/mol
Density of the solution = 1.09 g/mL
Step 2:
Assume the mass of the solution is 1.00 gram
⇒ 17.0 % CH3COONa = 0.17 grams
⇒ 83.0 % H2O = 0.83 grams
Step 3:
Density = 1.09 g/mL
Volume of the solution = total mass / density of solution
Volume of solution : 1.00 grams / 1.09 g/mL
Volume of the solution = 0.917 mL = 0.000917 L
Step 4: Calculate number of moles of CH3COONa
Number of moles = Mass / molar mass
Number of moles CH3COONa = 0.170 grams / 82.0 g/mol
Number of moles = CH3COONa = 0.00207 moles
Step 5: Calculate molarity
Molarity = moles / volume
Molarity solution =
0.00207 / 0.000917 L
Molarity solution = 2.26 mol/L = 2.26 M
The molarity of this solution is 2.26 M (option D)
