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sergeinik [125]
3 years ago
15

Twice the sum of a number and 3 times a second number is 4. The difference of ten times the seco

Mathematics
1 answer:
34kurt3 years ago
4 0

Two numbers that gives twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90 are -10  and 4

Given :

Twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90.

Let a  and b be the two  unknown numbers

Lets frame equation using the given statements

Twice the sum of a number and 3 times a second number is 4.

2(a+3b)=4\\a+3b=2

the difference of ten times the second number and five times the first is 90

10b -5a=90\\Divide \; by \;5 \\2b-a=18

Now use these two equations to solve a  and b

a+3b=2\\-a+2b=18

Add both the equations

a+3b=2\\-a+2b=18\\--------------------------\\5b=20\\b=4

Now find out 'a'

a+3b=2\\a+3(4)=2\\a+12=2\\a=2-12\\a=-10

The two numbers are -10  and 4

Learn more :  brainly.com/question/13856304

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Only false statements have counterexamples. true or false
ycow [4]
I think it is false, because you can have a contradicting statement to a true statement
5 0
3 years ago
Which are the roots of the quadratic function f(b) = 62 – 75? Select two options.
elena55 [62]

Answer:

b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

Step-by-step explanation:

Given

f(b) = b^2 - 75

Required

Determine the roots

To get the root of the function, then f(b) must be 0;

i.e. f(b) = 0

So, the expression becomes

0 = b^2 - 75

Add 75 to both sides

75 + 0 = b^2 - 75 + 75

75 = b^2

Take square roots of both sides

\sqrt{75} = \sqrt{b^2}

\sqrt{75} = b

Reorder

b = \sqrt{75}

Expand 75 as a product of 25 and 3

b = \sqrt{25*3}

Split the expression

b = \sqrt{25} *\sqrt{3}

b = \±5 *\sqrt{3}

b = \±5 \sqrt{3}

b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

The options are not clear enough; however the roots of the equation are b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

4 0
3 years ago
In the rectangular prism below, the length of MR is 8 inches, the length of RS is 9 inches, and the length of ST is 12 inches.Wh
kari74 [83]
84 is your awnser if i helped i hope im in fourth grade so dont judge
6 0
3 years ago
Read 2 more answers
Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?
erik [133]

Let

A-----> \frac{7}{8}

B-----> \frac{11}{10}

C-----> 1

we know that

Point A-------> Multiply numerator and denominator by 10

\frac{7*10}{8*10} =\frac{70}{80}

Point B-------> Multiply numerator and denominator by 8

\frac{11*8}{10*8} =\frac{88}{80}

Point C-------> Multiply numerator and denominator by 80

\frac{1*80}{1*80} =\frac{80}{80}

Find the distance Point A to Point C

\frac{80}{80} -\frac{70}{80} =\frac{10}{80}

Find the distance Point B to Point C

\frac{88}{80} -\frac{80}{80} =\frac{8}{80}

therefore

\frac{8}{80} < \frac{10}{80}

Point B is closer to Point C

\frac{11}{10} is closer to 1

the answer is

\frac{11}{10} is closer to 1

5 0
3 years ago
Read 2 more answers
Can someone help me with this prooblem
Scorpion4ik [409]

Answer:

9.85

Step-by-step explanation:

I hate these, LOL

We're going to draw a triangle on the graph paper to solve this. (in theory)

The top point is at 2 on the x axis, and the bottom is at 6. That's a difference of 4. Draw a line from the top dot over 4 spaces, so a line dropped from there could go straight to the bottom dot. We'll call this line/side of the triangle a, and a = 4.

Then we drop the line from there (6, 4) down to the second dot at (6, -5). That line is 9 places long. We'll call this line/side of the triangle b, and b = 9.

(This is so much easier to draw than type, I'll attach a picture).

Then we connect the two dots diagonally to form line/side c of our triangle. This is the length we don't know.

The pythagorean theorem says a^2 + b^2 = c^2

So a = 4, b = 9, c is unknown for our triangle

(4)(4) + (9)(9) = c^2

16 + 81 = 97

The square root of 97 = 9.8488, so if they have you round, I would say 9.85

Sorry if this just confused you more.

5 0
3 years ago
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