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deff fn [24]
3 years ago
9

One of the angles in a triangle measures 8/5

Mathematics
1 answer:
qaws [65]3 years ago
5 0

right angle = 90°

8/5 of 90° = (90° : 8) x 5

11,25 x 5 = 56,25°

It is a right triangle.

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What’s the area of this figure
kvasek [131]

Answer:

743.25m^2

Step-by-step explanation:

Area of triangle = 1/2bh

= 1/2 x 30 x 26

= 390

Area of semi circle = 1/2 πr^2

= 1/ 2 x 3.14 x 15 x15

=353.25m^2

= 390 + 353.25

= 743.25m^2

8 0
3 years ago
Read 2 more answers
An advertising blimp hovers over a stadium at an altitude of 125 m. The pilot sights a tennis court at and 8° angle of depressio
tatuchka [14]

Answer:

Hence the ground distance is about 889m between stadium and Tennis court.

Step-by-step explanation:

Given:

A pilot at height of 125 m(flying the advertising blimp)

angle of depression=8 degrees.

To find :

The ground distance  stadium and tennis court.

Solution :

Using Trigonometric Function we can solve it ,

(Refer the attachment for fig)

Considering above data we get a triangle(ABC)

with point A represent pilot position and C court position and B as stadium.

The height AB=125 m

angle of depression= 8 degrees.

Using

<em>tan∅ =AB/BC</em>

tan(8)=125/BC

BC=125/tan(8)

=125/0.14054

=889.2

=889 m

Hence the ground distance is about 889m between stadium and Tennis court.

6 0
4 years ago
In the diagram below, transversal t intersects parallel lines I and m.
Black_prince [1.1K]

Step-by-step explanation:

x+10=116

x=116-110

=106

x=106

6 0
3 years ago
Andy’s dog weighs 27 pounds, which is 3/4 the weight of Seher’s dog. How many pounds does Seher’s dog weigh?
spayn [35]

Answer:

20.25 lbs

Step-by-step explanation:

Multiply 27 by 3/4 or .75 to equal 20.25.

8 0
3 years ago
Read 2 more answers
In triangle ABC, a = 9, c = 5, and B = 120°. Find b2.
anygoal [31]

Answer:

(D) b^2=151

Step-by-step explanation:

Given: In triangle ABC, a=9, c=5 and ∠B=120°.

To find: The value of b^2.

solution: It is given that In triangle ABC, a=9, c=5 and ∠B=120°.

Now, using the law of cosines, we get

b^2=a^2+c^2-2(a)(c)cosB

Substituting the given values, we get

b^2=9^2+5^2-2(9)(5)cosB

b^2=81+25-90(\frac{-1}{2})

b^2=81+25+45

b^2=151

which is the required value of b^2.

Therefore, option D is correct.

3 0
3 years ago
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