Y2 + x2 = 53
y − x = 5
y = 5 + x
(5+x)^2 + x^2 = 53
(5+x)(5+x) + x^2 = 53
25 + 10x + x^2 +x^2 = 53
2x^2 + 10x - 28 = 0
(x-2)(x+7)=0
x = 2 , x = - 7
y = 5 + 2
y = 7
y = 5 +(-7)
y = 5 - 7
y = - 2
Answer:
QC - PB = 6
Step-by-step explanation:
Given PQ is parallel to BC then it divides the sides proportionally, that is
=
=
=
, then
=
( cross- multiply )
8PB = 5QC → *
Given PB + QC = 26 , then
PB = 26 - QC
Substitute into *
8(26 - QC) = 5QC ← distribute left side
208 - 8QC = 5QC ( subtract 5QC from both sides )
208 - 13QC = 0 ( subtract 208 from both sides )
- 13QC = - 208 ( divide both sides by - 13 )
QC = 16
Thus PB = 26 - QC = 26 - 16 = 10
QC - PB = 16 - 10 = 6
20+17c if c is 50 or under and 20+15.80c if c is more than 50
Answer:
x = 3
Step-by-step explanation:
24 = 9x -3
(add 3)
27 = 9x
(÷9)
x = 3
I think it is (10,-7) but lmk otherwise