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Aleksandr-060686 [28]
2 years ago
6

Is the statement below always something or never true give at least two examples to support your reasoning the LCM of two number

s is the product of two numbers discuss your conditions with a partner
Mathematics
1 answer:
Mashcka [7]2 years ago
3 0

Answer:

Sometimes, it is true

Step-by-step explanation:

The L. C. M of two numbers could be the product of the two Given numbers. This happens sometimes but not always. For instance, the Lowest Common. Multiple of 4 and 5 is 20

4 : 4, 8, 12, 16, 20, 24, 28, 32

5 : 5, 10, 15, 20, 25,...

L. C. M = 20 ; 4 * 5 = 20

However, L. C. M of 4 and 8

4 : 4, 8, 12, 16, 20, 24, 28, 32

8 : 8, 16, 24, 32, 40

L.C.M = 8 ; 4 * 8 = 32

HENCE, L. C. M could be the product of the 2 numbers sometimes and it may not in other scenarios.

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2 years ago
Please help me with this homework
snow_lady [41]

Answer:

10.44 m

Step-by-step explanation:

Solve this as a triange. The base is 3m and the perpendicular is 10m. The angle between the base and wall is 90° so it will be a right angled triangle.

Solve this by Pythagoras theorm:

let length of ladder is c

base is b

And perpendicular is a

Acc to Pythagoras theorem:

C² = a² + b²

C² = 10² + 3²

C² = 100 + 9

C² = 109

√C² = √109

C = 10.44m

8 0
2 years ago
1. How many squares will it take<br> to cover the figure below?
Ne4ueva [31]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
If you wanted to shift the graph of y = 2x + 5 up, which equation could you
S_A_V [24]

Answer: the answer is

A. y=2x+9

8 0
3 years ago
Read 2 more answers
find the value of a and b for which the system of equations has infinitely many solutions : 2x + 3y = 7 ; (a-b)x + (a+b)y = 3a +
hodyreva [135]

Answer:

a= 5    and   b=1

Step-by-step explanation:

To solve, we will follow the steps below:

2x + 3y = 7

(a-b)x + (a+b)y = 3a + b - 2​

We should note that since it has infinitely many solutions then,

\frac{a_{1} }{a_{2} }   =  \frac{b_{1} }{b_{2} }  = \frac{c_{1} }{c_{2} }

Hence

2/a-b  =  3/a+b   =     7/3a +b-2

2/a-b  =  3/a+b

cross-multiply

3(a-b) = 2( a+b)

open the bracket

3a - 3b = 2a + 2b

collect like term

3a - 2a = 2b + 3b

a = 5b  -------------------------------------------(1)

Similarly

3/a+b   =     7/3a +b-2

cross-multiply

7(a+b)  = 3(3a+b -2)

7a + 7b = 9a + 3b -6

take all the variables to the left-hand side of the equation

7a - 9a+ 7b-3b =   -6

-2a + 4b = -6 ---------------------------------(2)

but a = 5b

substitute a= 5b in equation (2)   and solve for b

-2(5) + 4b = -6

-10  +  4b  = -6

add 10 to both-side of the equation

-10  + 10+ 4b  = -6+10

4b = 4

divide both-side of the equation by 4

b = 1

substitute b= 1 in equation (1)

a = 5b

a =5(1)

a=5

Therefore,   a= 5    and   b=1

8 0
3 years ago
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