Given the following sequences 1,2,4,8,12 .... Find the sum of the first term

Identifying equivalent statements and negations of a conditional statement: help

Vitek1552 [10]

Answer:

1: Equal

2: Negation

3: Negation

4: Neither

Step-by-step explanation:

Sorry if I got any of them wrong

6 0

3 years ago

Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology ex

Nataly [62]

Answer:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion female for Biology

$\hat p_A =\frac{84199}{144796}=0.582$ represent the estimated proportion female for biology

$n_A=144796$ is the sample size for A

$p_B$ represent the real population proportion female for calculus AB

$\hat p_B =\frac{102598}{211693}=0.485$ represent the estimated proportion female for Calculus AB

$n_B=211693$ is the sample size required for B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

5 0

3 years ago

Help me!! With this until question fifteen thank you

Novay_Z [31]

Look up the.name of the book online with anser sheet I had that same book just find the page

6 0

3 years ago

Evaluate 6+x6+x6, plus, x when x=3?

vampirchik [111]

Answer:

42

Step-by-step explanation:

x=3

6+x6+x6

6+(3)6+(3)6

6=6

(3)6=18

6+18+18

24+18

42

Hope this helps ;) ❤❤❤

8 0

3 years ago

Read 2 more answers

You ride your bike x miles per hour up a mountain for 45 minutes. On the way down the mountain, you ride your bike 3 miles per h

denpristay [2]

Answer:

18/5 miles

Step-by-step explanation:

let d be the mountain dist path

upward biking

x miles - 1 hr

d 45 mins

3x/4 = d

riding down

x+3 - 60 min

d. - 20

(1/3)(x+3) = d

(x+3)/3 = 3x/4

4x+12 = 9x

x = 12/5

d =( 12*3)/(4*5)= 9/5

upward+downward = 2*(9/5) = 18/5

7 0

3 years ago

Given the following sequences 1,2,4,8,12 .... Find the sum of the first term​

Given the following sequences 1,2,4,8,12 .... Find the sum of the first term