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3 years ago

A gas is expanded from an initial volume of 1 L at 1 atm at 7 °C to a final volume of 5 L.

Chemistry

1 answer:

WITCHER [35]3 years ago

4 0

Answer:

0.40 atm

Explanation:

To answer this problem we can use the <em>combined gas law</em>:

T₂P₁V₁ = T₁P₂V₂

In this case:

T₂ = 287 °C ⇒ 287 + 273.16 = 560.16 K

P₁ = 1 atm

V₁ = 1 L

T₁ = 7 °C ⇒ 7 + 273.16 = 280.16 K

P₂ = ?

V₂ = 5 L

We <u>input the data</u>:

560.16 K * 1 atm * 1 L = 280.16 K * P₂ * 5 L

And <u>solve for P₂</u>:

P₂ = 0.40 atm

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1.302 moles of carbon dioxide would have to be added

<h3>Further explanation</h3>

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

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Reaction :

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initially 0.2 0.2 0.75+x 0.75

reaction 0.1 0.1 0.1 0.1

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$\displaystyle Kc=\frac{(0.650+x)(0.65)}{0.3.0.3}\\\\14.1(0.09)=0.4225+0.65x\\\\1.269-0.4225=0.65x\\\\0.8465=0.65x\\\\x=1.302$

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