SO we need 5 numbers that equal to 20, with 5 being the middle number, and ones being the most used number so
1 1 5 x y
According to this, x and y must equal 13 and both be bigger then 5. Because we can rule out every other number, x and y must be 6 and 7.
Your 5 numbers are 1, 1, 5, 6, 7.
Answer:
Victor originally had $80
Step-by-step explanation:
Let Victor have $4x
Let Susie have $7x
Since Victor spent half his money, he now has $2x
Susie spent $60 and thus now has $(7x - 60)
The final ratio of Victor's money to Susie's money is therefore 2x : $(7x - 60). This is given 1:2. Now we just need to solve the proportion by cross-multiplying
2x : (7x - 60) = 1:2
1 × (7x - 60) = 2 × 2x
7x - 60 = 4x
3x = 60
x = 20
Therefore Victor originally had $4x = $80.
The options can be rewrited as follow:
A. 5<4
B. 5<5
C. 5<4
D. 4<-5
∴ Answer is none of the above.
Unless perhaps you have written down the question incorrectly.
Answer:
A?? because I think it's not linear because it's not proportional
