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natima [27]
2 years ago
11

1. A time study analyst timed an assembly operation for 30 cycles, and then computed the average time per cycle, which was 18.75

minutes. The analyst assigned a performance rating of .96, and decided that an appropriate allowance was 15%. Assume the allowance factor is based on the workday. Determine the following: observed time (OT), the normal time (NT), and the standard time (ST)
Business
1 answer:
WARRIOR [948]2 years ago
5 0

Answer:

1. observed time = 18.75 minutes.

2. Normal time = 18 minutes

3. Standard time = 21.17 minutes

Explanation:

1. The observed time will be equal to the average time per cycle, which was given in the question as 18.75 min. Therefore, observed time = 18.75 minutes.

2. The normal time will be:

= Average Time x Performance Rating

= 18.75 x 0.96

= 18 minutes

3. The standard time will be:

= Normal time × 1/(1 - 15%)

= Normal time × 1/(1 - 0.15)

= 18 × 1/0.85

= 18 × 1.176

= 21.17 minutes

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2 years ago
How often will you receive a statement for your checking account?
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3 years ago
50 PTS!!!!!!!!!!!!
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Read 2 more answers
A company issued 5%, 20-year bonds with a face amount of $60 million. The market yield for bonds of similar risk and maturity is
Lesechka [4]

Answer:

Total $53.0656 (millions)

Explanation:

We will need to add the present value of the coupon payment

and the present value of the maturity date

<u>present value of the annuity:</u>

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C= 60 million x 5% /2 1.5

time= 20 years 2 payment per year = 40

rate = 6% annual = 0.06/2 = 0.03 semiannually

1.5 \times \frac{1-(1+0.03)^{-40} }{0.03} = PV\\

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<u>present value of the bonds:</u>

\frac{Maturity}{(1 + rate)^{time} } = PV

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time 40

rate           0.03

\frac{60}{(1 + 0.03)^{40} } = PV

PV        $18.3934

<u>The value of the bond will be the sum of both</u>

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PV m  $18.3934

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7 0
2 years ago
A machine to manufacture fasteners has a setup cost of $1,100 and a unit cost of $0.007 for each fastener manufacture. A new mac
Ludmilka [50]

Answer:

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Cost 1=1100+0,007*122222

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Cost 2=1650*0,0025*122222

Cost 2=1955,55

4 0
3 years ago
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