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SOVA2 [1]
3 years ago
11

An ant and a stone are on a circular disc, which is rotating at a constant speed. The stone is fixed to the disc. The ant is mov

ing along the rim in the opposite direction and at the same speed as that of the disc. Which of these shows the position of the ant and the stone after the disc completes 3/4th of a revolution?
Biology
1 answer:
Fittoniya [83]3 years ago
6 0

Find attached the options

Answer:

The option B in the attached is correct

Explanation:

In the given scenario the ant and stone are on the same disc and the stone is fixed.

The disc is moving at a constant speed in a clockwise direction while the ant is moving in the opposite direction.

The starting position is also attached with the ant opposite the stone.

So for a full rotation the ant would have gone round and met up with the stone.

If the disc completes a 3/4th revolution it will be at the position in B. The ant would have gotten to the stone by half revolution, and by 3/4th revolution it would have gone a quarter of the disc from the stone as shown

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Galactosemia is inherited as a homozygous recessive trait (i.e.,gg). You have sampled a population in which 36% of people have g
murzikaleks [220]

Answer:

a. The frequency of the g allele= 0.6

b. The frequency of the G allele= 0.4

c. The frequency of the GG genotype= 0.16 or 16%

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Explanation:

According to the given information, the disorder is homozygous recessive trait. The frequency of the homozygous recessive genotype (gg) in the population (q^2)= 36% or 0.36

Therefore, the frequency of the recessive allele "g" (q) = square root of 0.36= 0.6

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The frequency of the dominant allele "G" (p)= 0.4

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The frequency of heterozygous dominant genotype Gg = 2pq = 2 x 0.6 x 0.4 = 0.48 = 48%

7 0
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The transfer of energy as electromagnetic waves is called
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