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Alika [10]
3 years ago
9

A rectangular painting is to have a total area (including the frame) of 1200 cm2. If the painting is 30 cm long and 20 cm wide,

find the width of the frame
Mathematics
1 answer:
Leno4ka [110]3 years ago
3 0

Answer:

5 cm

Step-by-step explanation:

Let x = width of frame.

The width of the frame is added all around the painting, so you must add 2x to the length of the painting and 2x to the width of the painting to find the total length and width including the frame.

painting length: 30

total length: 2x + 30

painting width: 20

total width: 2x + 20

total area = LW

total area = (2x + 30)(2x + 20)

total area = 1200

(2x + 30)(2x + 20) = 1200

(x + 15)(x + 10) = 300

x^2 + 10x + 15x + 150 = 300

x^2 + 25x - 150 = 0

(x - 5)(x + 30) = 0

x - 5 = 0  or  x + 30 = 0

x = 5  or x = -30

The width of the frame cannot be a negative number, so we discard the solution x = -30.

Answer: 5 cm

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A. What is the value of x?<br> b. What is the measure of<br> angle B?
Papessa [141]

Answer:

a. x=4\sqrt{3}

b.  m\angle B =60\°

Step-by-step explanation:

a. The sides of an Equilateral triangle are all equal.

Then, in this case:

AB=BC=CA=8

Based on this, you can identify that AD divides the side BC into two equal parts and the triangle into two equal Right triangles. Then:

CD=BD=\frac{8}{2}=4

Knowing the length CD, you can find "x" using the Pythagorean Theorem. This is:

a^2=b^2+c^2

Where "a" is the hypotenuse and "b" and "c" are the legs.

In this case:

a=8\\b=x\\c=4

Substituting values and solving for "x", you get:

8^2=x^2+4^2\\\\\sqrt{8^2-4^2}=x\\\\x=4\sqrt{3}

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8 0
3 years ago
83. Use properties of exponents to rewrite each expression with only positive, rational exponents. Then find the numerical value
alexdok [17]

Answer:

2^{\frac{18}{11}}

Step-by-step explanation:

The given expression is

\sqrt[11]{y^2z^4}

The exponent property \sqrt[n]{x^ay^b}=x^{a/n}y^{b/n}

Applying this exponent property, we have

\sqrt[11]{y^2z^4}\\\\=y^{2/11}z^{4/11}

Now, the given numeric values are x = 9, y= 8, and z= 16

On substituting these values in the simplified expression, we get

(2)^{2/11}(16)^{4/11}

This can be further simplified by writing 16=2^4

(2)^{2/11}(2^4)^{4/11}\\\\(2)^{2/11}(2)^{16/11}

Now, applying the product rule of exponent: x^a\cdot x^b=x^{a+b}

(2)^{2/11+16/11}\\\\=2^{\frac{18}{11}}

4 0
3 years ago
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