Do the math the same way you would if all the other variables were numbers. For linear equations such as these, you can
• subtract one side of the equation, so you get an equation equal to zero.
• factor out the variable of interest
• subtract all terms that don't have the variable as a factor
• divide by the coefficient of the variable.
19. 2xy - x - 7 = 0 . . . . subract the right side
x(2y-1) -7 = 0 . . . . factor out x
x(2y -1) = 7 . . . . subtract the term(s) not containing x. Subtract -7 here.
x = 7/(2y -1) . . . . divide by the coefficient of x
20. Usually for these, you would eliminate fractions first. (You don't have to, but it does simplify things a bit.)
2d + f = 24 . . . . multiply the equation by 4 to eliminate fractions
f = 24 - 2d . . . . subtract the term not involving f
21. We can go back to the above sequence of steps here, if you like.
3(2j -k) -108 = 0 . . . . subtract the right side
6j -3k -108 = 0 . . . . separate the j terms from the others (eliminate parentheses using the distributive property)
6j = 108 + 3k . . . . add the opposite of the non-j terms
j = 108/6 + 3k/6 . . . . divide by the coefficient of j
j = 18 + k/2 . . . . simplify
22. "solve for" variable not specified.
t = (3.5s -42)/4
s = (4t+42)/3.5
In both cases, the 3.5 can be replaced by 7/2 and the fraction simplified.
t = (7/8)(s-12)
s = 12 + (8/7)t
Answer:
Step-by-step explanation:
{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1{-x+ 2 x < 1 S-x + 2 x > 1
a.y =
x+1 x 21
C. y =
x + 1
x < 1
-x+ 2 x < 1
b.y = {
x +1 x > 1
= {
d. y - 1
s-x + 2 x 2 1
x+1
x < 1
Answer:
The answer so simplyfjdjdnxkxndndjxjfnfngkdjsjajajjdjfj the answer is D
This equation if finding x would be 88
If A = (0,2,3,4,9,11), B = {2,3,6,8,9,10) and C= {0,2,3,9), then (A-B) n(A-C) is
timofeeve [1]
Answer:
(A-B)n(A-C) ={ }
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