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gogolik [260]
2 years ago
7

Help pleaseeeee eeeeeeee

Mathematics
1 answer:
omeli [17]2 years ago
8 0
A) n x 2.0
b) n x 2.0 = y

Hope this helps :)
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select all of the figures shown below that are unit cubes. (please explain what a unit cube is too and how to find one)
Marat540 [252]

Answer:

Unit Cube - Definition with Examples. A unit cube, sometimes called a cube of side 1, is a cube whose sides are 1 unit long. The volume of a 3-dimensional unit cube is 1 cubic unit, and its total surface area is 6 square units.

4 0
3 years ago
Which of the following equations is of a parabola with a vertex at (3, 0)?
bixtya [17]

Answer:

D. y = (x - 3)²

Step-by-step explanation:

The parabola formula in vertex form is:

y = a(x - h)² + k

where the vertex is located at (h, k). Replacing with vertex (3, 0) we get:

y = a(x - 3)² + 0

y = a(x - 3)²

In all possible options the leading coefficient <em>a</em> is equal to one. Therefore:

y = (x - 3)²

7 0
2 years ago
Determine if the two triangles are congruent. If they are, state how you know.
alexira [117]
They are congruent by SSS. (Side-side-side)

The two outside pairs of sides are stated as congruent.

The inside side is congruent by reflective property

We have 3 congruent sides, so the triangle is congruent by SSS
3 0
2 years ago
397 students went on a field trip. Eight
lbvjy [14]

Answer:48

Step-by-step explanation:

Total number of students=397

Students that travelled in a car=29

Let the students that travelled in a bus be represented by y.

Since 8 buses were filled, it will be 8y for total students

8y + 29= 397

8y= 397-29

8y= 368

Divide both side by 8

8y/8=368/8

y = 46

Number of students in each bus is 46

8 0
3 years ago
Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.
adoni [48]

again, let's assume daily compounding means 365 days per year.

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}

A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}

what's their difference?  well

\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}

7 0
1 year ago
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