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GuDViN [60]
3 years ago
7

A local health club has a large swimming pool non member must pay a 6$ per day fee to use the pool member of the club pay 1$ but

must pay a yearly membership fee of 250 how many days must you use the pool to justify joining the club
Mathematics
1 answer:
vazorg [7]3 years ago
3 0

Answer:

50 days

Step-by-step explanation:

Step one:'

given data

Non member must pay a 6$ per day

let number of days be x

cost = 6x

member of the club pay 1$ but must pay a yearly membership fee of 250

cost = 250+x

Step two

equate the two expression to find x

6x=250+x

6x-x= 250

5x=250

divide both sides by 5

x= 250/5

x=50 days

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14w^9- 19w^9<br> Help please
zhuklara [117]

Answer:

-5w^9.

Step-by-step explanation:

These two terms are what we call, 'like terms'. This means that they are terms whose variables and exponents are the same. 14w^9- 19w^9 have the variable w^9 in common.

In these cases, all we do is use the coefficients (the number in front of the variable). Hence, 14w^9- 19w^9, quite literally turns into, 14-19. If we complete the sum, 14-19= -5. Put it all together, we have -5w^9.

Hope this helps!

4 0
3 years ago
Simplify 7j-6k-5j+4k which explanation please:)
Phantasy [73]
Step 1. <span>Gather like terms

</span>(7j-5j)+(-6k+4k)
<span>
Step 2. </span><span>Simplify

</span>2j-2k
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Done! Hope this helps :)</span>
4 0
3 years ago
Read 2 more answers
Jackson estimated 637 ÷ 78 as 640 ÷ 80. He reasoned that 64 tens divided by 8 tens should be 8 tens. Is Jackson’s reasoning corr
Sholpan [36]

Answer:

the correct solution has been explained

Step-by-step explanation:

Jackson,s reasoning is incorrect  because it should be 8 ones and not 8 tens that would give 64

\frac{640}{80} = \frac{64}{8} = 8

Moreover, \frac{637}{78}  is\ not\ equal\ to \frac{640}{8}

as \frac{637}{78}= 8.16

whereas \frac{640}{80} = 8

clearly, both quantities are different

7 0
3 years ago
Help help help help
Alex

Answer:

<h3>b=\frac{t-5}{4}</h3>

Step-by-step explanation:

4b+5=t

First, you must get the variable alone! Substract 5 from both sides!

4b<u>+5=t </u>

    -5  -5

The 5 cancels out because 5-5=0

The new equation is 4b=t-5

You must divide by 4 to get the variable alone since your solving for b!

<u>4b=t-5</u>

4      4

b= \frac{t-5}{4} \\

This is your answer!

5 0
3 years ago
PLEASE HELP! WILL GIVE BRAINLIEST!!
Maslowich

Your answer is -6+3i.

6 0
3 years ago
Read 2 more answers
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