Answer:
Step-by-step explanation:
x2+y2+ax+by+c=0
Step 1: Add -by to both sides.
ax+by+x2+y2+c+−by=0+−by
ax+x2+y2+c=−by
Step 2: Add -x^2 to both sides.
ax+x2+y2+c+−x2=−by+−x2
ax+y2+c=−bax+y2+c+−y2=−by−x2+−y2
ax+c=−by−x2−y2
Step 4: Add -c to both sides.
ax+c+−c=−by−x2−y2+−c
ax=−by−x2−y2−c
Step 5: Divide both sides by x.
ax
x
=
−by−x2−y2−c
x
a=
−by−x2−y2−c
x
y−x2
Answer:
Step-by-step explanation:
x = 0.6 m
F = 78 N
Let k be the spring constant.
F = k x
78 = 0.6 k
k = 130 N/m
(a)
x = 5.5 m
W = 0.5 kx²
W = 0.5 x 130 x 5.5 x 5.5
W = 7865 J
(B) x = 1.5 m
W = 0.5 kx²
W = 0.5 x 130 x 1.5 x 1.5
W = 146.25 J
The page is 12 inches wide. He wants to center the photo that is 3 1/2 inches wide. So, you do 12 - 3 1/2 (3.5), which equals 8.5. Then, because the page has 2 sides (obviously), you do 8.5 ÷ 2, so your answer is 4.25 (4 1/4) :)
P.S you are not stupid :)
Problem 1
Answers:
- Choice A) Cylinder
- Choice C) Rectangular prism
- Choice D) Rectangular pyramid
Reason:
Refer the diagram below to see how rectangular cross sections are possible. The cross sections are marked in red.
For the rectangular prism, we could have a vertical or horizontal plane. For the cylinder, only a vertical cross section is possible. On the flip side, a rectangular pyramid can only have horizontal rectangular cross sections (which are similar to the base).
========================================================
Problem 2
Answer: Approximately 73,280.62908 square feet
Explanation:
Calculate the area of the trapezoid. Ignore the small triangle for now.
A = h*(b1+b2)/2
A = 354*(266+158)/2
A = 75,048
Now calculate the area of the triangle we ignored earlier
Before we do this, we'll need to use the pythagorean theorem to find the missing horizontal piece
a^2 + b^2 = c^2
b = sqrt(c^2 - a^2)
b = sqrt(97^2 - 40^2)
b = 88.368546 which is approximate.
Now we can find the area of the small triangle
Area = base*height/2 = 88.368546*40/2 = 1,767.37092
This is to be subtracted from the area of the trapezoid we found earlier.
75,048 - 1,767.37092 = 73,280.62908
Round the result however you need to.