Answer: Equivalent
Step-by-step explanation:
There is the same amount of red filling in the boxes in both.
Answer:
![\frac{\sqrt[3]{5} }{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3x%7D)
Step-by-step explanation:
Ok, let's do this step by step....
![\sqrt[3]{\frac{10x^{5} }{54x^{8} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10x%5E%7B5%7D%20%7D%7B54x%5E%7B8%7D%20%7D%20%7D)
Let's first simplify the x's:
![\sqrt[3]{\frac{10}{54x^{3} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10%7D%7B54x%5E%7B3%7D%20%7D%20%7D)
Then we breakdown the 54 as 2 * 27 then simplify with the 10 above.
![\sqrt[3]{\frac{10}{2 * 27x^{3} } } = \sqrt[3]{\frac{5}{27x^{3} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10%7D%7B2%20%2A%2027x%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B5%7D%7B27x%5E%7B3%7D%20%7D%20%7D)
Now, we can rewrite this as the following and solve the bottom part:
![\frac{\sqrt[3]{5} }{\sqrt[3]{27x^{3} } } = \frac{\sqrt[3]{5} }{3 \sqrt[3]{x^{3} } } = \frac{\sqrt[3]{5} }{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B%5Csqrt%5B3%5D%7B27x%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3%20%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3x%7D)
The solution is
![\frac{\sqrt[3]{5} }{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3x%7D)
Answer:
6.79 x 10 to the power of 3
Step-by-step explanation:
6790 divided by 1000 is 6.79
Assuming you are solving for x
do the opposite of PEMDAS. Isolate the x. Because of equal sign, what you do to one side, you do to the other.
x/5 + 9 = 4
x/5 + 9 (-9) = 4 (-9)
x/5 = 4 - 9
x/5 = -5
x/5(5) = -5(5)
x = -5(5)
x = -25
-25 is your answer for x
hope this helps