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3 years ago

Which graph shows the solution set for Negative 4.4 greater-than-or-equal-to 1.6 x minus 3.6?

Mathematics

2 answers:

____ [38]3 years ago

8 0

Answer:

A number line going from negative 7 to negative 1. A closed circle is at negative 5. Everything to the right of the circle is shaded.

Step-by-step explanation:

-4.4 ≥ 1.6 x - 3.6

Solving for the value of x,

1.6 x ≤ -4.4 + 3.6

1.6 x ≤ - 0.8

Dividing 1.6 from both sides to know value of x

x ≤ - 0.5

natima [27]3 years ago

6 0

Answer:

-5 and less

Step-by-step explanation:

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0.39+0.11= adding decimals

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I believe the answer is 0.5 sorry if I’m wrong

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HELP ME IM SO CONFUSED

givi [52]

Answer:

1) 4812 students
2) 763 pounds
3) $30906.76

Step-by-step explanation:

Initial number = 2988
Rate of increase = 10%

Number of students after 6 years:

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Rate of decrease = 14%

Amount of gold after 4 years:

$a_4=1200(1-0.14)^3 = 763$

Initial number = 28000
Rate of increase = 2.5%

Salary after n years:

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3 years ago

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write an equation in slope intercept form of the line with a slope- 2 and y intercept 3. Graph the line

charle [14.2K]

Answer:

y = -2x + 3

Step-by-step explanation:

Step 1: Find out what each part of slope intercept form is

Slope Intercept Form: y = mx + b

m is the slope

b is the y-intercept

Step 2: Plug in the information into the formula

m/slope = -2

b/y-int = 3

y = -2x + 3

Answer: y = -2x + 3

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3 years ago

Help meeeeeeeeeeee pls

PtichkaEL [24]

Answer:

with what lol?

Step-by-step explanation:

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3 years ago

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Find the distance traveled by a particle with position (x, y as t varies in the given time interval. x = 3?sin2 t, y = 3?cos2 t,

ANTONII [103]

Assuming the particle's position is given by

$\begin{cases}x(t)=3-\sin2t\\y(t)=3-\cos2t\\0\le t\le4\end{cases}$

then the distance traveled over the interval is

$\displaystyle\int_{t=0}^{t=4}\sqrt{\left(\dfrac{\mathrm dx(t)}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy(t)}{\mathrm dt}\right)^2}\,\mathrm dt$
$=\displaystyle\int_0^4\sqrt{(-2\cos2t)^2+(2\sin2t)^2}\,\mathrm dt$
$=\displaystyle\int_0^4\sqrt{4\cos^22t+4\sin^22t}\,\mathrm dt$
$=\displaystyle2\int_0^4\mathrm dt$
$=2(4-0)=8$

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3 years ago