Answer:
infinitely many answers, any odd integer n times π/2
ex. π/2, 3π/2, 5π/2
Step-by-step explanation:
we know that cos (π/2) or cos(3π/2) is 0
if one factor is 0, the product is zero, so we will not care about csc(x).
x is any odd integer n times π/2
Answer:
y=-5x+1
Step-by-step explanation:
y-y1=m(x-x1)
y-(-9)=-5(x-2)
y+9=-5x+10
y=-5x+10-9
y=-5x+1
$50x2.2%
50x0.022=1.1
$50-$1.1=$48.9
The partial quotient is 23
Answers:
- Total equation: x+y = 80
- Legs equation: 2x+4y = 248
- How many ducks? 36
- How many cows? 44
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Further explanation:
- x = number of ducks
- y = number of cows
x+y = 80 is the total equation (ie the head count equation) since we assume each animal has 1 head, and there are 80 heads total.
That equation can be solved to y = 80-x after subtracting x from both sides.
The legs equation is 2x+4y = 248 because...
- 2x = number of legs from all the ducks only
- 4y = number of legs from all the cows only
- 2x+4y = total number of legs from both types of animals combined
We're told there are 248 legs overall, so that's how we ended up with 2x+4y = 248
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Let's plug y = 80-x into the second equation and solve for x.
2x+4y = 248
2x+4( y ) = 248
2x+4( 80-x ) = 248
2x+320-4x = 248
-2x+320 = 248
-2x = 248-320
-2x = -72
x = -72/(-2)
x = 36
There are 36 ducks
Now use this x value to find y
y = 80-x
y = 80-36
y = 44
There are 44 cows.
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Check:
36 ducks + 44 cows = 80 animals total
36*2 + 44*4 = 72 + 176 = 248 legs total
The answers are confirmed.
