Answer:
5 hours
Step-by-step explanation:
Time taken for trip : t + 1
Time taken for return : t
Avg. speed (trip) : 256 km/h
Avg. speed (return) : 320 km/h
The distances covered on both trips are equal.
⇒ Distance (trip) = Distance (return)
⇒ Speed (trip) × time (trip) = Speed (return) × time (return)
⇒ (256)(t + 1) = (320)(t)
⇒ 256t + 256 = 320t
⇒ 64t = 256
⇒ t = 4 hours
<u>Time (trip)</u> = t + 1 = 4 + 1 = 5 hours
Colors are Qualitative and Nominal: Qualitative, because there is no number involved for "color" and Nominal, because their is no natural ordering for color
The distance of the plane flies between the two cities is 1,113.75 miles
The formula for calculating the distance travelled is expressed as:
D = vt where:
v is the speed
t is the time taken
Given the following:
v = 99mi/hr
Total time taken = 5hr + 6.25hr
Total time taken = 11.25hr
Get the required distance
Distance = 99mi/hr * 11.25hr
Distance = 1,113.75miles
Hence the distance of the plane flies between the two cities is 1,113.75 miles
learn more here: brainly.com/question/7245260
Answer:
60 degrees
Step-by-step explanation:
Angles 1 and 2 are "corresponding angles" and as such are equal. Thus, the measure of angle 2 is 60 degrees.
Answer:
1/5 + 2/5 i sqrt(6) = .2 + .98i
1/5 - 2/5 i sqrt(6) = .2 - .98i
Step-by-step explanation:
5z^2−9z=−7z−5
We need to get all the terms on one side (set the right side equal to zero)
Add 7z to each side
5z^2−9z+7z=−7z+7z−5
5z^2−2z=−5
Add 5 to each side
5z^2−2z+5=−5 +5
5z^2−2z+5=0
This is in the form
az^2 +bz+c = 0 so we can use the quadratic formula
where a = 5 b = -2 and c = 5
-b± sqrt(b^2-4ac)
-------------------------
2a
-(-2)± sqrt((-2)^2-4(5)5)
-------------------------
2(5)
2± sqrt(4-100)
-------------------------
10
2± sqrt(-96)
-------------------------
10
2± sqrt(16)sqrt(-1) sqrt(6)
-------------------------
10
2± 4i sqrt(6)
-------------------------
10
1/5 ± 2/5 i sqrt(6)
Splitting the ±
1/5 + 2/5 i sqrt(6) = .2 + .98i
1/5 - 2/5 i sqrt(6) = .2 - .98i
