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Elden [556K]
3 years ago
5

Decrease £2155.45 by 18.5% Give your answer rounded to 2 DP ​

Mathematics
2 answers:
VMariaS [17]3 years ago
5 0
1756.70
I don’t know what else to add but that’s it
RSB [31]3 years ago
3 0

Answer:

£1756.70

Step-by-step explanation:

2155.45 * .185 = 398.75825

21.55.45 - 398.75825 = 1756.69175

Hope this helps

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-2(csc2θ - cot2θ)<br> - 1 <br> -2<br> -3<br> -1
Lorico [155]

Answer:

- 2

Step-by-step explanation:

- 2( { \csc}^{2}  \theta \:  -  {cot}^{2}  \theta)  \\  =  - 2(1) \\  =  - 2

8 0
3 years ago
Help please ! It’s geometry
bearhunter [10]

Answer:

90 °

Step-by-step explanation:

\sqrt{5 \times 12}

\sqrt[5]{3}

\sqrt{6 \times 5}

\sqrt[5]{3}

6 0
3 years ago
A particle is projected with a velocity of <img src="https://tex.z-dn.net/?f=40ms%5E-%5E1" id="TexFormula1" title="40ms^-^1" alt
Katena32 [7]

Answer:

2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be y. The magnitude of 40\text{ m/s} will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is 60^{\circ}, we have:

\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}(Recall that \sin 60^{\circ}=\frac{\sqrt{3}}{2})

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation v_f^2=v_i^2+2a\Delta y to solve this problem, where v_f/v_i is final and initial velocity, respectively, a is acceleration, and \Delta y is distance travelled. The only acceleration is acceleration due to gravity, which is approximately 9.8\:\mathrm{m/s^2}. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

  • v_i=20\sqrt{3}\text{ m/s}
  • a=-9.8\:\mathrm{m/s^2}
  • \Delta y =50\text{ m}

Solving for v_f:

v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}

3 0
3 years ago
Rewrite the subtraction number sentence as an addition number sentence.<br>5- (-2)<br>​
GrogVix [38]

Answer:

5 + 2          

Step-by-step explanation:

We have to rewrite the given statement in addition form.

The integers have  property of:

Negative(-)  Negative(-) = Positive(+)

Positive(+)  Positive(+)  = Positive(+)

Positive(+)  Negative(-) = Negative(-)

Negative(-) Positive(+)  = Negative(-)

The given statement is:

5-(-2)

Since we have two negative together, it is converted into a positive.

Thus, the given statement can be written in positive form as

5 + 2

4 0
3 years ago
Estimate 55+3<br> to the hundred the<br> place,
pentagon [3]

Answer:

100

Step-by-step explanation:

8 0
3 years ago
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